int到unsigned int转换 [英] int to unsigned int conversion

问题描述

  int i = 
我非常惊讶地知道我无法通过转换将signed转换为unsigned int。 -62; 
 unsigned int j =（unsigned int）i; 
  

我以为我已经知道这一点，因为我开始使用casts，但是我不能做！

解决方案

您可以将 int 转换为 unsigned int 。

由于值为负数，因此会向其中添加 UINT_MAX + 1 因此该值是有效的无符号数量。 （技术上，2 ^N 被添加到其中，其中N是用于表示无符号类型的位数。）

，因为您的平台上的 int 宽度为32位，从2 ³² 中减去62，得到4,294,967,234。

I'm just amazed to know that I can't convert signed to unsigned int by casting!

int i = -62;
unsigned int j = (unsigned int)i;

I thought I already knew this since I started to use casts, but I can't do it!

解决方案

You can convert an int to an unsigned int. The conversion is valid and well-defined.

Since the value is negative, UINT_MAX + 1 is added to it so that the value is a valid unsigned quantity. (Technically, 2^N is added to it, where N is the number of bits used to represent the unsigned type.)

In this case, since int on your platform has a width of 32 bits, 62 is subtracted from 2³², yielding 4,294,967,234.

这篇关于int到unsigned int转换的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！