如何将unsigned char *值复制到unsigned char? [英] How to Copy unsigned char* value to unsigned char?

问题描述

如何将unsigned char *值复制到unsigned char ???

How to Copy unsigned char* value to unsigned char???

推荐答案

您是否在问如何这样做:

Are you asking how you do this:

void GetChar(unsigned char *pointer)
   {
   unsigned char uc = *pointer;
   }

因为如果您愿意，我认为您需要更仔细地阅读课程笔记...

Because if you are, I think you need to look at your course notes a little more carefully...

Gokulnath007写道:

Gokulnath007 wrote:

是的.要迭代.

好吧，指针基本上是一个数组(相反，数组基本上是一个指针).
字符串是字符数组，后跟空字符''\0''.
所以，

Well, a pointer is basically an array (rather, an array is basically a pointer).
A string is an array of characters followed by the null character ''\0''.
so,

char *str = "hello world";
for (int ch = 0; str[ch] != ''\0''; ++ch) { //keep going until we hit the ''\0''
    printf("%c\n", str[ch]); //print a single character and jump to the next line
}

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