如何将char * str复制到C中的char c []? [英] How to copy char *str to char c[] in C?
本文介绍了如何将char * str复制到C中的char c []?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
尝试将 char * str
复制到 char c []
,但得到分段错误或无效的初始化程序错误。
Trying to copy a char *str
to char c[]
but getting segmentation fault or invalid initializer error.
为什么此代码会给我 seg错误
Why is this code is giving me a seg fault?
char *token = "some random string";
char c[80];
strcpy( c, token);
strncpy(c, token, sizeof c - 1);
c[79] = '\0';
char *broken = strtok(c, "#");
推荐答案
/* code not tested */
#include <string.h>
int main(void) {
char *src = "gkjsdh fkdshfkjsdhfksdjghf ewi7tr weigrfdhf gsdjfsd jfgsdjf gsdjfgwe";
char dst[10]; /* not enough for all of src */
strcpy(dst, src); /* BANG!!! */
strncpy(dst, src, sizeof dst - 1); /* OK ... but `dst` needs to be NUL terminated */
dst[9] = '\0';
return 0;
}
这篇关于如何将char * str复制到C中的char c []?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文