如何在 C 中将 char *str 复制到 char c[]? [英] How to copy char *str to char c[] in C?

问题描述

试图将 char *str 复制到 char c[] 但出现分段错误或无效初始化程序错误.

Trying to copy a char *str to char c[] but getting segmentation fault or invalid initializer error.

为什么这段代码给我一个seg fault?

Why is this code is giving me a seg fault?

char *token = "some random string";
char c[80];  
strcpy( c, token);
strncpy(c, token, sizeof c - 1); 
c[79] = '';
char *broken = strtok(c, "#");

推荐答案

使用strncpy() 而不是 strcpy()

/* code not tested */
#include <string.h>

int main(void) {
  char *src = "gkjsdh fkdshfkjsdhfksdjghf ewi7tr weigrfdhf gsdjfsd jfgsdjf gsdjfgwe";
  char dst[10]; /* not enough for all of src */

  strcpy(dst, src); /* BANG!!! */
  strncpy(dst, src, sizeof dst - 1); /* OK ... but `dst` needs to be NUL terminated */
      dst[9] = '';
  return 0;
}

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