深层复制std :: string :: c_str（）to char * [英] Deep copy std::string::c_str() to char *

问题描述

目前我有一个复杂的功能，我和我们的团队不想重构利用std :: string，它需要一个char *被修改。我如何正确地做一个深度复制的字符串:: c_str（）成一个char *？我不要修改字符串的内部存储的char *。

Currently I have a complex function that myself and our team are not wanting to refactor to utilize std::string and it takes a char* which is modified. How would I properly make a deep-copy of string::c_str() into a char*? I am not looking to modify the string's internally stored char*.

char *cstr = string.c_str();

失败，因为c_str（）是const。

fails because c_str() is const.

推荐答案

你可以这样做：

const std::string::size_type size = string.size();
char *buffer = new char[size + 1];   //we need extra char for NUL
memcpy(buffer, string.c_str(), size + 1);

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