数组初始值设定项/转换为指针 [英] array initializer / conversion to pointer
问题描述
你好，
我有一个非常简单的问题。我希望有类似的东西
int
main（）
{
double array [ 3] [3] = {{1,2,3}，{4,5,6}，{7,8,9}};
double ** field;
field = array;
}
编译器在作业中抱怨不允许转换
field = array;
该字段的类型为double **是必要的。如何管理如上所述的
初始化？
问候，
alex
Hello,
I''ve got a quite simple question. I want to have something like
int
main()
{
double array[3][3] = {{1,2,3}, {4,5,6}, {7,8,9}};
double **field;
field = array;
}
The compiler complains an not allowed conversion in the assignment
field = array;
It''s neccessary that field is of type double**. How to manage an
initialization like the above?
regards,
alex
推荐答案
Alexander Stippler< st ** @ mathematik.uni-ulm.de>潦草地写道：
Alexander Stippler <st**@mathematik.uni-ulm.de> scribbled the following:
你好，
我有一个非常简单的问题。我希望有一些像
int
main（）
{/ / double array [3] [3] = {{1,2,3}，{4,5， 6}，{7,8,9}};
双**字段;
字段=数组;
}
编译器在作业中抱怨不允许转换
field = array;
字段是double **类型是必要的。如何管理如上所述的
初始化？
Hello, I''ve got a quite simple question. I want to have something like int
main()
{
double array[3][3] = {{1,2,3}, {4,5,6}, {7,8,9}};
double **field;
field = array;
} The compiler complains an not allowed conversion in the assignment
field = array;
It''s neccessary that field is of type double**. How to manage an
initialization like the above?
将字段声明为double（* field）[3]。
-
/ - Joona Palaste（pa*****@cc.helsinki.fi）-------------芬兰--- ----- \
\ - http： //www.helsinki.fi/~palaste ---------------------规则！ -------- /
更强，没有。黑暗面更具诱惑力，狡猾，更脆弱。
- Mika P. Nieminen
Declare field as double (*field)[3] instead.
--
/-- Joona Palaste (pa*****@cc.helsinki.fi) ------------- Finland --------\
\-- http://www.helsinki.fi/~palaste --------------------- rules! --------/
"Stronger, no. More seductive, cunning, crunchier the Dark Side is."
- Mika P. Nieminen
Alexander Stippler写道：
Alexander Stippler wrote:
你好，
我有一个非常简单的问题。我希望有类似的东西
主要的（）
{/ />双数组[3] [3] = {{1,2,3}，{ 4,5,6}，{7,8,9}};
双**字段;
字段=数组;
}
编译器抱怨不允许在作业中进行转换
field = array;
该字段的类型为double **是必要的。如何管理如上所述的
初始化？
Hello,
I''ve got a quite simple question. I want to have something like
int
main()
{
double array[3][3] = {{1,2,3}, {4,5,6}, {7,8,9}};
double **field;
field = array;
}
The compiler complains an not allowed conversion in the assignment
field = array;
It''s neccessary that field is of type double**. How to manage an
initialization like the above?
这是常见问题解答。阅读常见问题6.18位于：
http ：//www.eskimo.com/~scs/C-faq/q6.18.html
正如常见问题所示，请这样做：
double（* field）[3] = array;
下面使用函数PrintARRAY显示一个示例，使用
typedef。
如果，正如你所说的那样，字段必须是双**类型，那么
你仍然可以以访问元素为代价来实现它
a稍微困难一些。这在下面的PrintARRAY2和
PrintARRAY3函数中显示。
#include< stdio.h>
#define ROW 3
#define COL 4
typedef double（* ARR）[COL];
void PrintARRAY（ARR row）;
void PrintARRAY2（double ** field）;
void PrintARRAY3（double ** field）;
int main（void）
{
double array [ROW] [COL] = {{1,2,3,11}，{4,5， 6,22}，{7,8,9,33}};
ARR this = array;
double ** field =（double **）array;
puts（使用函数PrintARRAY）;
PrintARRAY（this）;
puts（" \ nUsing function） printARRAY2"）;
PrintARRAY2（字段）;
puts（" \ nUsing function printARRAY3"）;
PrintARRAY3（field）;
返回0;
}
无效PrintARRAY（ARR行）
{
int i，j;
for（i = 0; i< ROW; i ++）
{
for（j = 0; j< COL; j ++）
printf（"％。2f"，row [i] [j]）;
putchar（''\ n''）;
}
返回;
}
无效PrintARRAY2（双**字段）
{
int i，j;
double（* arr）[COL] =（double（*）[COL]）字段;
for（i = 0; i< ROW; i ++，arr ++）
{
for（j = 0; j< COL ; j ++）
printf（"％。2f"，（* arr）[j]）;
putchar（''\ n''）;
}
返回;
}
无效PrintARRAY3（双**字段）
{
int i，j;
double * arr =（double *）field;
for （i = 0; i< ROW; i ++）
{
for（j = 0; j< COL; j ++）
printf（"％。2f"，arr [i * COL + j]）;
putchar（''\ n''）;
}
返回;
}
-
Al Bowers
Tampa，Fl USA
mailto： xa * *****@myrapidsys.com （删除x以发送电子邮件）
http://www.geocities.com/abowers822/
This is a faq question and answer. Read faq question 6.18 located:
http://www.eskimo.com/~scs/C-faq/q6.18.html
As the faq suggests, make this:
double (*field)[3] = array;
An example is shown below using in function PrintARRAY, using a
typedef.
If, as you say, it is neccessary that field be type double**, then
you can still do it at the expense of making access to the elements
a little more difficult. This is shown in functions PrintARRAY2 and
PrintARRAY3 below.
#include <stdio.h>
#define ROW 3
#define COL 4
typedef double (*ARR)[COL];
void PrintARRAY(ARR row);
void PrintARRAY2(double **field);
void PrintARRAY3(double **field);
int main(void)
{
double array[ROW][COL] = {{1,2,3,11}, {4,5,6,22}, {7,8,9,33}};
ARR this = array;
double **field = (double **)array;
puts("Using function PrintARRAY");
PrintARRAY(this);
puts("\nUsing function printARRAY2");
PrintARRAY2(field);
puts("\nUsing function printARRAY3");
PrintARRAY3(field);
return 0;
}
void PrintARRAY(ARR row)
{
int i,j;
for(i = 0; i < ROW;i++)
{
for(j = 0; j < COL; j++)
printf("%.2f ",row[i][j]);
putchar(''\n'');
}
return;
}
void PrintARRAY2(double **field)
{
int i,j;
double (*arr)[COL] = (double (*)[COL])field;
for(i = 0; i < ROW;i++,arr++)
{
for(j = 0; j < COL; j++)
printf("%.2f ",(*arr)[j]);
putchar(''\n'');
}
return;
}
void PrintARRAY3(double **field)
{
int i,j;
double *arr= (double *)field;
for(i = 0;i < ROW; i++)
{
for(j = 0; j < COL;j++)
printf("%.2f ",arr[i*COL+j]);
putchar(''\n'');
}
return;
}
--
Al Bowers
Tampa, Fl USA
mailto: xa******@myrapidsys.com (remove the x to send email)
http://www.geocities.com/abowers822/
Joona I Palaste写道：
Joona I Palaste wrote:
Alexander Stippler< st ** @ mathematik.uni-ulm.de>潦草地写道：
Alexander Stippler <st**@mathematik.uni-ulm.de> scribbled the following:
你好，
我有一个非常简单的问题。我希望有类似的东西
I''ve got a quite simple question. I want to have something like
int
main（）
{
double array [3] [3] = {{ 1,2,3}，{4,5,6}，{7,8,9}};
double ** field;
field = array;
}
int
main()
{
double array[3][3] = {{1,2,3}, {4,5,6}, {7,8,9}};
double **field;
field = array;
}
编译器在作业中抱怨不允许转换
field = array;
该字段的类型为double **是必要的。如何管理如上所述的
初始化？
The compiler complains an not allowed conversion in the assignment
field = array;
It''s neccessary that field is of type double**. How to manage an
initialization like the above?
将字段声明为double（* field）[3]而不是。
Declare field as double (*field)[3] instead.
对不起，但我不能影响字段的类型，因为我已经在
中提到了我的第一个帖子！它对我的影响是外在的。我需要它是
双**，那又怎么样？
最好的问候，alex
Sorry, but I cannot influence the type of field, as I already mentioned in
my first posting! It is ''external'' to my influence. I need it to be
double **, so what?
best regards, alex
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