K& R2，练习1-23 [英] K&R2, exercise 1-23
问题描述
没有编译时错误或警告。它运行但它没有按照它应该做的那样去做。
想要：打印输入C程序。删除所有评论。
GOT：不打印任何内容。
--------程序----- ------
/ * K& R2：练习1-23
声明：
写一个程序来删除来自C程序的所有评论
不要忘记正确处理引用的字符串和字符常量。
方法：
1.）该程序一次输入一行。它将所有
行（完整输入）复制到一个字符数组中。
2.）然后我们调用一个函数remove_comments。从输入中删除所有
注释。
3.）然后我们打印数组。现在不包含任何评论。
* /
#include< stdio.h>
＃定义MAXLENGTH 30000
int getline（char arr []）;
void remove_comments（char arr []）;
int main（）
{
int i = 0;
char arr [MAXLENGTH];
/ *初始化数组* /
for（i = 0; i< MAXLENGTH - 1; ++ i）
arr [i] = 0 ;
而（getline（arr））
;
remove_comments（arr）;
printf（" ------------------------- \\\
"）;
printf（"％s \\ \\ n"，arr）;
返回0;
}
int getline（char arr []）
{
int c = 0;
int i = 0;
for（i = 0; i< MAXLENGTH - 1&&（c = getchar（））！= EOF&& c！=''\ n'';
++ i）
arr [i] = c;
if（c ==''\ n''）
arr [i ++] = \ n'';
arr [i] =''\ 0'';
返回i;
}
void remove_comments（char arr []）
{
int i = 0;
int j = 0;
int incomment = 0;
char arr2 [MAXLENGTH -1];
代表（i = 0;我< MAXLENGTH - 1; ++ i）
arr2 [i] = 0;
for（i = 0; arr [i]！=''\ 0''; ++ i ）
{
if（arr [i]！=''"''）
{
if（arr [i] ==''/''&& arr [i + 1] ==''*''）
incomment = 1;
}
if（arr [i] ==''*''&& arr [i + 1] ==''/''&& arr [i + 2] ！=''"''）
incomment = 0;
if（incomment == 0）
arr2 [ j ++] = arr [i];
}
arr2 [j] =''\''';
for（i = 0; arr2 [i]！=''\ 0''; ++ i）
arr [i] = arr2 [i];
}
-----------输出----------------
[arch @ voodo kr2] $ gcc -ansi -pedantic -Wall -Wextra -O ex_1-23.c
[arch @ voodo kr2] $ ./a.out
喜欢这个
-------------------------
[arch @ voodo kr2] $
there are no compile-time errors or warning. it runs but it does not
do what it is supposed to.
WANTED: to print the "input C programme" with all comments removed.
GOT: does not print anything.
-------- PROGRAMME -----------
/* K&R2: exercise 1-23
STATEMENT:
write aprogramme to remove all comments from a C programme
dont forget to handle quoted strings and character constants properly.
METHOD:
1.) this programme gets its input a line at a time. it copies all the
lines (full input) into a characters array.
2.) we then call a function "remove_comments" which removes all the
comments from the input.
3.) we then print the "array" which now does not contain any comments.
*/
#include<stdio.h>
#define MAXLENGTH 30000
int getline(char arr[]);
void remove_comments(char arr[]);
int main()
{
int i = 0;
char arr[MAXLENGTH];
/* initialising array */
for(i = 0; i < MAXLENGTH - 1; ++i)
arr[i] = 0;
while(getline(arr))
;
remove_comments(arr);
printf("-------------------------\n");
printf("%s\n", arr);
return 0;
}
int getline(char arr[])
{
int c = 0;
int i = 0;
for(i = 0; i < MAXLENGTH - 1 && (c = getchar()) != EOF && c != ''\n'';
++i)
arr[i] = c;
if(c == ''\n'')
arr[i++] = ''\n'';
arr[i] = ''\0'';
return i;
}
void remove_comments(char arr[])
{
int i = 0;
int j = 0;
int incomment = 0;
char arr2[MAXLENGTH -1];
for(i=0; i < MAXLENGTH - 1; ++i)
arr2[i] = 0;
for(i=0; arr[i] != ''\0''; ++i)
{
if(arr[i] != ''"'')
{
if(arr[i] == ''/'' && arr[i+1] == ''*'')
incomment = 1;
}
if(arr[i] == ''*'' && arr[i+1] == ''/'' && arr[i+2] != ''"'')
incomment = 0;
if(incomment == 0)
arr2[j++] = arr[i];
}
arr2[j] = ''\0'';
for(i = 0; arr2[i] != ''\0''; ++i)
arr[i] = arr2[i];
}
----------- OUTPUT ----------------
[arch@voodo kr2]$ gcc -ansi -pedantic -Wall -Wextra -O ex_1-23.c
[arch@voodo kr2]$ ./a.out
like this
-------------------------
[arch@voodo kr2]$
推荐答案
gcc -ansi -pedantic -Wa ll -Wextra -O ex_1-23.c
[arch @ voodo kr2]
gcc -ansi -pedantic -Wall -Wextra -O ex_1-23.c
[arch@voodo kr2]
./ a.out
赞了这个
-------------------------
[arch @ voodo kr2 ]
./a.out
like this
-------------------------
[arch@voodo kr2]
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