在最后一次出现角色之前删除所有内容 [英] remove everything before the last occurrence of a character

问题描述

我正在尝试对字符串执行以下操作：

I'm trying to perform the following action on a string :

• 查找字符的最后一次出现/;


• 删除该字符前的所有内容;


• 返回字符串的剩余部分;

• find the last occurrence of the character "/";
• remove everything before that character;
• return the remains of the string;

为了更明确，假设我有以下字符串：

To be more explicit, let's say I have the following string :

var string = "/Roland/index.php"; // Which is a result of window.location.pathname

现在我需要提取它是除了实际页面之外的所有内容，如下所示：

Now what I need to extract out of it is everything but the actual page, something like this :

var result = "index.php" // Which is what I need to be returned

当然，这只是一个例子，因为很明显我会有不同的页面，但是同样的原则适用。

Of course, that is just an example, because obviously I will have different pages, but the same principles apply.

我想知道是否有人可以帮我解决问题。我尝试了下一步但没有成功：

I was wondering if someone could help me out with a solution for it. I tried the next actions but with no success :

var location = window.location.pathname;
var result = location.substring(location.lastIndexOf["/"]);

推荐答案

你有正确的想法只需用括号替换括号。

You have the right idea just replace the brackets with parentheses.

var string = "/Roland/index.php";
var result = string.substring(string.lastIndexOf("/") + 1);

以下是 jsfiddle ，这里是对 Mozilla开发者网络。

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