删除Swift数组中最后一次出现的元素 [英] Remove the last occurrence of an element in a Swift array

问题描述

我需要删除[Bool]数组中特定元素的最后一次出现.例如，在JavaScript中，将是:

I need to remove the last occurrence of a specific element in a [Bool] Array. For example in JavaScript this would be:

var k = [true, true, false];
k.splice(k.lastIndexOf(true), 1);
==> [true, false]

我将如何在Swift中实现相同的行为?

How would I achieve the same behavior in Swift?

推荐答案

通过反向枚举，您可以轻松找到值的最后一次出现.找到所需的值后，只需将其删除并退出循环即可.使用reverse()以相反的顺序枚举索引范围:

You can easily find the last occurrence of a value by enumerating in reverse. When you find the value you're looking for, just remove it and break from the loop. Use reverse() enumerate the range of indexes in reverse order:

for i in array.indices.reversed() where array[i] == searchValue {
    array.remove(at: i)
    break
}

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