用于网站或网址验证的正则表达式 [英] Regex for website or url validation

问题描述

我知道这是一个很常见的问题&有这么多答案，但我的问题不同，我想接受以下所有格式的网址：

I know this is so common question & there are so many answers for this, but my problem is different, I want to accept the URL with all below formats:

http://www.sample.com
https://www.sample.com
http://www.sample.com/xyz
www.sample.com
www.sample.com/xyz/#/xyz
sample.com

// & much more ...

所以这里的想法是，我允许用户进入那里的网站&另一个用户只需点击已保存的网站&去用户网站。因此，限制用户输入正确的URL并不是一个好主意，他们可以输入上述任何格式。这是我正在使用的正则表达式，但它只检查URL是否从正确的协议开始：

So here idea is, I am allowing the user to enter there website & another user can just click on the saved website & go to users website. So here it's not a good idea to restrict the user to input proper URL, they can enter any of the above formats. Here is the regex I am using right now, but that only checks if URL starts from proper protocol:

^(ftp|http|https):\/\/[^ "]+$

推荐答案

使用正则表达式 ^（（https？| ftp | smtp）：\ / \ /）？（www。）？[a-z0-9] + \。[ az] +（\ / [a-zA-Z0-9＃] + \ /？）* $

这是一个我刚刚建立的基本版本。谷歌搜索可以给你更多。

This is a basic one I build just now. A google search can give you more.

这里

• ^应该以


• 开头（（https？| ftp | smtp）：//）？可能包含或不包含任何这些协议


• （www.。）？可能有也可能没有www。


• [a-z0-9] +（。[az] +）url和域以及子域（如果有的话）最多2个级别


• （/ [a-zA-Z0-9＃] + /？）* /？可以包含文件的路径，但不是必需的。最后可能包含 /


• $应该在那里结束

• ^ Should start with
• ((https?|ftp|smtp)://)? may or maynot contain any of these protocols
• (www.)? may or may not have www.
• [a-z0-9]+(.[a-z]+) url and domain and also subdomain if any upto 2 levels
• (/[a-zA-Z0-9#]+/?)*/? can contain path to files but not necessary. last may contain a /
• $ should end there

var a=["http://www.sample.com","https://www.sample.com/","https://www.sample.com#","http://www.sample.com/xyz","http://www.sample.com/#xyz","www.sample.com","www.sample.com/xyz/#/xyz","sample.com","sample.com?name=foo","http://www.sample.com#xyz","http://www.sample.c"];
var re=/^((https?|ftp|smtp):\/\/)?(www.)?[a-z0-9]+(\.[a-z]{2,}){1,3}(#?\/?[a-zA-Z0-9#]+)*\/?(\?[a-zA-Z0-9-_]+=[a-zA-Z0-9-%]+&?)?$/;
a.map(x=>console.log(x+" => "+re.test(x)));

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