如果下一行重复忽略 [英] If next row duplicate ignore

问题描述

大家好，


我有一张足球比赛表，每个结果/行都有一个日期，年月日。


有些游戏的日期相同，我希望它只在第一次显示时显示相同的日期。


我尝试过使用下面的代码，但它只是检查日期是否存在。

我需要检查日期是否与prev相同


[PHP] if（（ $ gamedate）== 0）{

echo""

} else {

echo" $ gamedate";} [/ PHP]


希望你能帮忙


hinksta

解决方案

gamedate） == 0）{

echo""

} else {

echo"

gamedate" ;;} [/ PHP]


希望你能提供帮助


hinksta

如果您是从DB获取结果，然后在SQL查询中使用GROUP BY日期。

Hi all,

I have a table with football results, each result/row has a date, year-month-day.

Some games have the same date, I would like it to display the same date only the first time it is found.

I''ve tried using the code below but it only checks if a date is present or not.
I need something to check if the date is the same as prev or not

[PHP]if(($gamedate) == 0) {
echo ""
}else{
echo "$gamedate";}[/PHP]

Hope you can help

hinksta

解决方案

gamedate) == 0) {
echo ""
}else{
echo "

gamedate";}[/PHP]

Hope you can help

hinksta

If you are fetching the results from DB, then use GROUP BY date in your SQL query.

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