确定文件名是否大于X个字符 [英] Determining if a filename is greater than X characters

问题描述

如何确定文件名是否大于某个数字

的字符然后将其截断为该数字？例如，一个名为XXXXXXXXX.txt的文件名为XXXXXXXX.txt将成为XXXXXX


fname = files

如果fname [0]> 6

打印fname [0]


谢谢!!!

How would I determine if a filename is greater than a certain number
of characters and then truncate it to that number? For example a file
named XXXXXXXXX.txt would become XXXXXX

fname = files
if fname[0] > 6
print fname[0]

Thanks!!!

推荐答案

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如何确定文件名是否大于某个数字的字符数，然后将其截断为该数字？例如，名为XXXXXXXXX.txt的文件将成为XXXXXX

fname = files
如果fname [0]> 6
打印fname [0]
谢谢!!!

How would I determine if a filename is greater than a certain number
of characters and then truncate it to that number? For example a file
named XXXXXXXXX.txt would become XXXXXX

fname = files
if fname[0] > 6
print fname[0]

Thanks!!!

filename =" abcdefgh"

if len（filename）> 6：

filename =文件名[：6]

打印文件名

abcdef


-

Cy
http：// home。 rochester.rr.com/cyhome/

2003年8月2日星期六19:15，hokiegal99写道：

On Saturday 02 August 2003 19:15, hokiegal99 wrote:

我该怎么办？确定文件名是否大于特定数量的字符，然后将其截断为该数字？例如，名为XXXXXXXXX.txt的文件将成为XXXXXX

fname = files
如果fname [0]> 6
打印fname [0]
谢谢!!!

How would I determine if a filename is greater than a certain number
of characters and then truncate it to that number? For example a file
named XXXXXXXXX.txt would become XXXXXX

fname = files
if fname[0] > 6
print fname[0]

Thanks!!!

查看os.path模块和len（ ）内置。其中两个

应该能为您提供所需的一切。

look at the os.path module and also the len() builtin. The two of those
should give you everything you need.

Cy Edmunds写道：

Cy Edmunds wrote:

filename =" abcdefgh"
if len（filename）> 6：
filename = filename [：6]
打印文件名
abcdef

filename = "abcdefgh"
if len(filename) > 6:
filename = filename[:6]
print filename
abcdef

如果没有必要，只需使用


filename =文件名[：6]


- 图片

The if is not necessary, just use

filename=filename[:6]

--Irmen

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