.BAT重命名文件名中删除第一个X字符，最后x个字符 [英] .bat rename files name remove first x characters and last x characters

问题描述

我需要一些文件夹重命名文件，如解释它需要通过去除N位的字符和我集合X字符最后一个号码第一个数字一个文件夹中重命名文件名。
有人能告诉我该怎么做？

I need to rename files in some folder, like explained it needs to rename file names in one folder by removing first number of x characters and last number of x characters I set. Can someone show me how to do that?

推荐答案

在这里你去：

@echo off
setlocal enabledelayedexpansion
set X=3
set FOLDER_PATH=.
pushd %FOLDER_PATH%
for %%f in (*) do if %%f neq %~nx0 (
    set "filename=%%~nf"
    set "filename=!filename:~%X%,-%X%!"
    ren "%%f" "!filename!%%~xf"
)
popd

本脚本进入文件夹（ FOLDER_PATH 指定）和修剪第一个和最后一个 X 字符文件名（离开其扩展名是）。修改 X 和 FOLDER_PATH 是必要的。

This script enters the folder (specified by FOLDER_PATH) and trims the first and last X characters from the filename of each file (leaving its extension as is). Modify X and FOLDER_PATH as necessary.

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