创建节点时出错 [英] Error creating a node

问题描述

我正在创建自己的链表实现，只是为了获得一些稍微高级的C ++的基本知识。我有下面的课程，但我得到

错误说错误C2629：意外节点（'''在线上为

重叠构造函数Node（char xiType）

有谁可以告诉我哪里出错了？

谢谢

Allan

#include< iostream>


class Node

{

public：

Node（） ;

Node（char xiType）;

virtual~Node（）;


void SetNextLink（Node * xiNode）{NextNode = xiNode）;

void SetPrevLink（Node * xiNode）{PrevNode = xiNode};

Node * GetPrevLink（）{return PrevNode;}

节点* GetNextLink（）{return NextNode;}

void SetData（void * xiData）{Data = xiData;}

void * GetData（）{return Data;}

私人：

节点* NextNode;

节点* PrevNode;

void *数据;

bool Tail;

bool Head;

};

解决方案

" Allan Bruce" <人***** @ TAKEAWAYf2s.com>在消息新闻中写道：br ********** @ news.freedom2surf.net ...

我正在制作自己的链表实现只是为了得到一些基本的
了解更先进的C ++。我有下面的课程，但是我得到了一个错误，上面写着错误C2629：意外节点（'''在线上为重叠的构造函数Node（char xiType）

你确定上一行真的有一个分号吗？

" Ron Natalie"< ro*@sensor.com>写在消息中

新闻：3f * ********************@news.newshosting.com ..

Allan Bruce< al * **** @ TAKEAWAYf2s.com>写在留言

news：br ********** @ news.freedom2surf.net ...

我正在创建自己的链表实现，只是为了获得一些稍微高级的C ++的基本知识。我有下面的课程，但是我
得到一个错误说错误C2629：意外'节点（'''我i s为
为重叠的构造函数Node（char xiType）
任何人都可以告诉我哪里出错了吗？

你确定上一行是真的吗？最后有一个分号？

在此之前没有其他课程，但他们都有分号

在课程定义的最后。

Allan

Allan Bruce写道：

" Ron Natalie < ro*@sensor.com>在消息中写道
新闻：3f ********************* @ news.newshosting.com。 ..

" Allan Bruce" <人***** @ TAKEAWAYf2s.com>在消息中写道

新闻：br ********** @ news.freedom2surf.net ...

< blockquote class =post_quotes>我正在创建自己的链表实现，只是为了获得一些稍微高级的C ++的基本知识。我有下面的课程，但是我得到了一个错误，上面写着错误C2629：意外节点（'''在线就是

重叠构造函数Node（char xiType）
任何人都可以告诉我哪里出错了吗？

你确定上一行真的有一个分号吗？

在此之前没有其他类，但它们在类定义的末尾都有分号。
Allan

不，Ron的意思是你绝对确定在默认构造函数后面有分号，而不是冒号吗？

即你重新打字，或者你剪切和粘贴了吗？

I am making my own linked list implementation just to get some basic
knowledge of slightly more advanced C++. I have the class below, but I get
an error saying "error C2629: unexpected ''Node (''" which is on the line for
the overlaoded constructor Node(char xiType)
Can anybody tell me where I am going wrong?
Thanks
Allan
#include <iostream>

class Node
{
public:
Node();
Node(char xiType);
virtual ~Node();

void SetNextLink(Node *xiNode){NextNode = xiNode);
void SetPrevLink(Node *xiNode){PrevNode = xiNode);
Node *GetPrevLink(){return PrevNode;}
Node *GetNextLink(){return NextNode;}
void SetData(void *xiData){Data = xiData;}
void *GetData(){return Data;}
private:
Node *NextNode;
Node *PrevNode;
void *Data;
bool Tail;
bool Head;
};

解决方案

"Allan Bruce" <al*****@TAKEAWAYf2s.com> wrote in message news:br**********@news.freedom2surf.net...

I am making my own linked list implementation just to get some basic
knowledge of slightly more advanced C++. I have the class below, but I get
an error saying "error C2629: unexpected ''Node (''" which is on the line for
the overlaoded constructor Node(char xiType)
Can anybody tell me where I am going wrong?

Are you sure the previous line really has a semicolon at the end of it?

"Ron Natalie" <ro*@sensor.com> wrote in message
news:3f*********************@news.newshosting.com. ..

"Allan Bruce" <al*****@TAKEAWAYf2s.com> wrote in message

news:br**********@news.freedom2surf.net...

I am making my own linked list implementation just to get some basic
knowledge of slightly more advanced C++. I have the class below, but I get an error saying "error C2629: unexpected ''Node (''" which is on the line for the overlaoded constructor Node(char xiType)
Can anybody tell me where I am going wrong?

Are you sure the previous line really has a semicolon at the end of it?

There are no other classes before this one, but they do all have semi-colons
at the end of the class definitions.
Allan

Allan Bruce wrote:

"Ron Natalie" <ro*@sensor.com> wrote in message
news:3f*********************@news.newshosting.com. ..

"Allan Bruce" <al*****@TAKEAWAYf2s.com> wrote in message

news:br**********@news.freedom2surf.net...

I am making my own linked list implementation just to get some basic
knowledge of slightly more advanced C++. I have the class below, but I
get
an error saying "error C2629: unexpected ''Node (''" which is on the line
for
the overlaoded constructor Node(char xiType)
Can anybody tell me where I am going wrong?

Are you sure the previous line really has a semicolon at the end of it?

There are no other classes before this one, but they do all have semi-colons
at the end of the class definitions.
Allan

No, Ron meant are you absolutely sure that you have a semicolon after the default constructor, and not a colon?
i.e. did you retype, or did you cut&paste?

这篇关于创建节点时出错的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！