祖先:: XML语法 [英] ancestor:: XML syntax
问题描述
是否有人熟悉使用祖先的正确语法::？
我试图在ac＃应用程序中使用它，我是还在名为Cooktop的
解析器应用程序中进行测试（ http：// www。 xmlcooktop.com ）
我无法使用它或我的c＃代码在使用祖先时返回节点列表。
是祖先::某事.NET支持还是不支持？
示例，这些都不起作用：
nodes：// pallet / ancestor :: position
<！ - nodes xpath // pallet / ancestor :: position'' - >
<！ - nodes xpath parent :: * / pallet / position / *'' - >
<！ - nodes xpath parent :: * // pallet / position / *'' - >
<！ - nodes xpath / ancestor :: position / client [@id =''MDR'']'' - >
<！ - nodes xpath / pallet / ancestor： ：position / client [@id =''MDR'']'' - >
<！ - 节点xpath / pallet / position / ancestor :: client [@id =''MDR'']'' - >
for
< pallet> ;
< position row =" 0"托架= QUOT; 0" level =" A">
< client id =" HAL">
< partnum id =" HA0132-1033" isStock =" N"> HA0132-1033< / partnum>
< partnum id =" HA9027EP" isStock =" Y"> HA9027EP< / partnum>
< / client>
< client id =" MDR">
< partnum id =" A / P FILES" isStock =" N"> A / P FILES< / partnum>
< / client>
< client id =" OPS">
< partnum id =" OPS" isStock =" N" OPS
< / partnum>< / client>
< / position>
< position row =" 1"托架= QUOT 1 QUOT; level =" B">
< client id =" MDR">
< partnum id =" A / P FILES" isStock =" N" A / P FILES
< / partnum>
< / client>
< / position> ;
< position row =" 1"托架= QUOT 1 QUOT; level =" D">
< client id =" MDR">
< partnum id =" X-MAS DECORATION" isStock =" N"> X-MAS装饰
< / partnum>
< / client>
< / pallet> ;
Is anyone familar with the correct syntax for using ancestor:: ?
I am trying to use it in a c# application, and I am also testing it in a
parser application called Cooktop ( http://www.xmlcooktop.com )
I cannot get it or my c# code to return a node list when using ancestor.
Is ancestor:: something that .NET does or does not support?
Examples, none of these work:
nodes://pallet/ancestor::position
<!--nodes xpath //pallet/ancestor::position''-->
<!--nodes xpath parent::*/pallet/position/*''-->
<!--nodes xpath parent::*//pallet/position/*''-->
<!--nodes xpath /ancestor::position/client[@id=''MDR'']''-->
<!--nodes xpath /pallet/ancestor::position/client[@id=''MDR'']''-->
<!--nodes xpath /pallet/position/ancestor::client[@id=''MDR'']''-->
for
<pallet>
<position row="0" bay="0" level="A">
<client id="HAL">
<partnum id="HA0132-1033 " isStock="N">HA0132-1033 </partnum>
<partnum id="HA9027EP " isStock="Y">HA9027EP </partnum>
</client>
<client id="MDR">
<partnum id="A/P FILES " isStock="N">A/P FILES </partnum>
</client>
<client id="OPS">
<partnum id="OPS " isStock="N">OPS
</partnum></client>
</position>
<position row="1" bay="1" level="B">
<client id="MDR">
<partnum id="A/P FILES " isStock="N">A/P FILES
</partnum>
</client>
</position>
<position row="1" bay="1" level="D">
<client id="MDR">
<partnum id="X-MAS DECORATION" isStock="N">X-MAS DECORATION
</partnum>
</client>
</pallet>
推荐答案
John Bailo写道：
John Bailo wrote:
示例，这些都不起作用：
节点：//托盘/祖先::位置
<托盘>
< ; position row =" 0"托架= QUOT; 0" level =" A">
< client id =" HAL">
< partnum id =" HA0132-1033" isStock =" N"> HA0132-1033< / partnum>
< partnum id =" HA9027EP" isStock =" Y"> HA9027EP< / partnum>
< / client>
< client id =" MDR">
< partnum id =" A / P FILES isStock =" N"> A / P FILES< / partnum>
< / client>
< client id =" OPS">
< partnum id = OPS isStock =" N"> OPS
< / partnum>< / client>
< / position>
< position row =" 1"托架= QUOT 1 QUOT; level =" B">
< client id =" MDR">
< partnum id =" A / P FILES" isStock =" N"> A / P FILES
< / partnum>
< / client>
< / position>
< position row =" 1 QUOT;托架= QUOT 1 QUOT; level =" D">
< client id =" MDR">
< partnum id =" X-MAS DECORATION" isStock =" N"> X-MAS装饰
< / partnum>
< / client>
< / pallet>
Examples, none of these work:
nodes://pallet/ancestor::position
<pallet>
<position row="0" bay="0" level="A">
<client id="HAL">
<partnum id="HA0132-1033 " isStock="N">HA0132-1033 </partnum>
<partnum id="HA9027EP " isStock="Y">HA9027EP </partnum>
</client>
<client id="MDR">
<partnum id="A/P FILES " isStock="N">A/P FILES </partnum>
</client>
<client id="OPS">
<partnum id="OPS " isStock="N">OPS
</partnum></client>
</position>
<position row="1" bay="1" level="B">
<client id="MDR">
<partnum id="A/P FILES " isStock="N">A/P FILES
</partnum>
</client>
</position>
<position row="1" bay="1" level="D">
<client id="MDR">
<partnum id="X-MAS DECORATION" isStock="N">X-MAS DECORATION
</partnum>
</client>
</pallet>
位置元素是托盘元素的子元素，所以我不会理解为什么你需要
//托盘/祖先:: position
如果你想访问位置元素，那么你需要
/托盘/位置
-
Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/
Martin Honnen写道：
Martin Honnen wrote:
位置元素是托盘元素的子元素所以我不喜欢't
理解你为什么要
//托盘/祖先::位置
如果你想访问位置元素那么你需要
/托盘/位置
The position elements are children of the pallet element so I don''t
understand why you want
//pallet/ancestor::position
If you want to access the position elements then you need
/pallet/position
所以，我想返回包含客户的所有POSITION节点，其中
id是M DR。
但我唯一想要的POSITION孩子是ID为MDR的客户。
如果我这样做
/托盘/位置/客户[@id =''MDR''] / ..
我获得所有职位，但所有职位都在这些职位上，而不仅仅是
客户的id =''MDR''
所以，从我的示例XML，如果我做了一个xpath来隔离@ id =' 'MBR''，我会像这样将
作为我的退货清单：
< pallet>
< position行= QUOT; 0"托架= QUOT; 0" level =" A">
< client id =" MDR">
< partnum id =" A / P FILES" isStock =" N"> A / P FILES< / partnum>
< / client>
< / position>
< position row =" 1"托架= QUOT 1 QUOT; level =" B">
< client id =" MDR">
< partnum id =" A / P FILES" isStock =" N" A / P FILES
< / partnum>
< / client>
< / position> ;
< position row =" 1"托架= QUOT 1 QUOT; level =" D">
< client id =" MDR">
< partnum id =" X-MAS DECORATION" isStock =" N"> X-MAS装饰
< / partnum>
< / client>
< / pallet> ;
这就是为什么我以为我会使用祖先，找到所有的客户端节点，然后每个客户端节点的祖先是
（我认为这将排除每个位置节点的其他
子节点）。
So, I want to return all the POSITION nodes that contain CLIENTS whose
id is MDR.
But the only children of POSITION I want are the CLIENTS whose id is MDR.
If I do
/pallet/position/client[@id=''MDR'']/..
I get all the POSITIONS, but all CLIENTS in those positions, not just
CLIENTS whose id = ''MDR''
So, from my example XML, if I did an xpath to isolate @id=''MBR'', I would
like this to be my return list:
<pallet>
<position row="0" bay="0" level="A">
<client id="MDR">
<partnum id="A/P FILES " isStock="N">A/P FILES </partnum>
</client>
</position>
<position row="1" bay="1" level="B">
<client id="MDR">
<partnum id="A/P FILES " isStock="N">A/P FILES
</partnum>
</client>
</position>
<position row="1" bay="1" level="D">
<client id="MDR">
<partnum id="X-MAS DECORATION" isStock="N">X-MAS DECORATION
</partnum>
</client>
</pallet>
That''s why I thought I''d use ancestor, to find all the clientnodes, and
then each client node''s ancestor (which I think will exclude the other
child nodes of each position node).
看起来你想要使用descendant ::而不是祖先::
-
Greg Collins [微软MVP]
访问Brain Trove（ http://www.BrainTrove.com ）
It looks like you are wanting to use descendant:: rather than ancestor::
--
Greg Collins [Microsoft MVP]
Visit Brain Trove ( http://www.BrainTrove.com )
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