遍历XSD [英] Traversing XSD

问题描述

您好，

有没有办法使用XPath遍历XSD。我的研究表明没有

传统方式，但我想知道是否有解决方法。

感谢您的帮助和时间。

Hi there,
Is there a way to traverse an XSD using XPath. My research indicates no
conventional way of doing it, but I was wondering if there was a work around.
Thanks for your help and time.

推荐答案

MMA写道：

MMA wrote:

有没有办法遍历XSD使用XPath。我的研究表明没有传统的方法，但我想知道是否有解决方法。

Is there a way to traverse an XSD using XPath. My research indicates no
conventional way of doing it, but I was wondering if there was a work around.

XSD是带命名空间的XML，因此使用XPath XSD文件可能是
。如果您需要有关特定XPath的帮助，请告诉我们

架构的详细信息。


..NET还提供XML架构对象模型（SOM）它允许你以结构化的

的方式提取模式的类型/元素/属性定义，参见

< http：// msdn.microsoft.com/library/default.asp?url=/library/en-us/cpguide/html/cpconxsdschemaobjectmodelsom.asp>

-


Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/

我不完全确定你的意思是遍历。


但是，XML Schema是用xml（故意）所以你可以

肯定会对它评估XPath表达式：


例如。

<？xml version = " 1.0" encoding =" ISO-8859-1"？>

< xsd：schema xmlns =" http：//Dickster.com"

xmlns：xsd = " HTTP：//www.w3.org/2001/XMLSchema" =" http://Dickster.com">


< xsd：element name =" person">

< xsd： complexType>

< xsd：sequence>

< xsd：element name =" firstname" type =" xsd：string" />

< xsd：element name =" surname" type =" xsd：string" />

< / xsd：sequence>

< / xsd：complexType>

< ; / xsd：element>

< / xsd：schema>


eg

XPath表达式// xsd：element [@name =''surname'']返回

xsd：element节点，该节点有一个名为''name'的属性设置为

''surname''

I''m not fully sure what you mean by traverse.

However, XML Schema is written in xml (intentionally) so you can
certainly evaluate XPath expressions against it:

eg.
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsd:schema xmlns="http://Dickster.com"
xmlns:xsd="http://www.w3.org/2001/XMLSchema" ="http://Dickster.com">

<xsd:element name="person">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="firstname" type="xsd:string"/>
<xsd:element name="surname" type="xsd:string"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>

e.g.
The XPath expression //xsd:element[@name=''surname''] returns the
xsd:element node which has an attribute called ''name'' set to
''surname''

XML Schema是用xml编写的（有意）

因此你当然可以根据它来评估XPath表达式：


例如。


< xsd：schema xmlns =" http：//Dickster.com"

xmlns：xsd = http：//www.w3.org/2001/XMLSchema"

targetNamespace =" http://Dickster.com">


< xsd：element name =" person">

< xsd：complexType>

< xsd：sequence>

< ; xsd：element name =" firstname" type =" xsd：string" />

< xsd：element name =" surname" type =" xsd：string" />

< / xsd：sequence>

< / xsd：complexType>

< ; / xsd：element>

< / xsd：schema>


eg

XPath表达式// xsd：element [@name =''surname'']返回

xsd：element节点，该节点有一个名为''name'的属性设置为

''surname''

XML Schema is written in xml (intentionally)
Therefore you can certainly evaluate XPath expressions against it:

eg.

<xsd:schema xmlns="http://Dickster.com"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://Dickster.com">

<xsd:element name="person">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="firstname" type="xsd:string"/>
<xsd:element name="surname" type="xsd:string"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>

e.g.
The XPath expression //xsd:element[@name=''surname''] returns the
xsd:element node which has an attribute called ''name'' set to
''surname''

这篇关于遍历XSD的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！