这合法吗？ [英] Is it legal?
问题描述
你好，
写合法是否合法
printf（"％+ *。* f"，5,0， A [r] [c]）;
而不是
printf（"％+ 5.0f"，A [r] [ c]）;
感谢
xhungab写道：
< blockquote class =post_quotes>
你好，
写合法是否合法
printf（"％+ *。 * f"，5,0，A [r] [c]）;
而不是
printf（"％+ 5.0 f，A [r] [c]）;
感谢
嗨！
是的，例如GNU C库，如
http://www.gnu.org/software/libc/man...atted%20Output 。
但他们也说其他C库版本可能无法识别这种语法。
康斯坦丁
你好，
写合法是否合法
printf（" ％+ *。* f"，5,0，A [r] [c]）;
而不是
printf（" ;％+ 5.0f"，A [r] [c]）;
感谢
你的意思是+在里面 ？看起来很讨厌。你为什么要这样做？
这样做？
尝试在C90 / C99模式下调用编译器，具体取决于你想要的
标准坚持，并启用严格/迂腐模式。
Sh
Schraalhans Keukenmeester写道：
xhungab写道：
>你好，
写作是否合法
printf（"％+ *。* f"，5,0，A [r] [c]）;
而不是
printf（" ％+ 5.0f"，A [r] [c]）;
感谢
你的意思是+中的+？看起来很讨厌。你为什么要这样做？
这样做？
尝试在C90 / C99模式下调用编译器，具体取决于你想要的
标准坚持，并启用严格/迂腐模式。
Sh
+有什么问题？
kmi
Hello,
Is it legal to write
printf(" %+*.*f",5,0,A[r][c]);
Instead of
printf(" %+5.0f",A[r][c]);
Thank
xhungab wrote:
Hello,
Is it legal to write
printf(" %+*.*f",5,0,A[r][c]);
Instead of
printf(" %+5.0f",A[r][c]);
ThankHi!
Yes it is for example with GNU C library as said in
http://www.gnu.org/software/libc/man...atted%20Output.
But they also say "Other C library versions may not recognize this syntax."
Konstantin
xhungab wrote:Hello,
Is it legal to write
printf(" %+*.*f",5,0,A[r][c]);
Instead of
printf(" %+5.0f",A[r][c]);
Thank
You mean with the + in it ? Looks yucky anyways. Why would you want to
do this like that?
Try invoking your compiler in C90 / C99 mode, depending on which
standard you want to adhere to, and enable strict/pedantic mode.
Sh
Schraalhans Keukenmeester wrote:
xhungab wrote:>Hello,
Is it legal to write
printf(" %+*.*f",5,0,A[r][c]);
Instead of
printf(" %+5.0f",A[r][c]);
Thank
You mean with the + in it ? Looks yucky anyways. Why would you want to
do this like that?
Try invoking your compiler in C90 / C99 mode, depending on which
standard you want to adhere to, and enable strict/pedantic mode.
ShWhat is wrong with the + ?
kmi
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