如何访问LONGLONG值的各个字节 [英] How to access the individual bytes of LONGLONG value

问题描述

有人能告诉我如何访问包含Windows LONGLONG值的
的单个字节吗？

Hi,
Could anybody tell me how to access the individual bytes that consists
of a Windows LONGLONG value?

推荐答案

2006-03-21，shaji< sh *********** @ gmail.com>写道：

On 2006-03-21, shaji <sh***********@gmail.com> wrote:

有人能告诉我如何访问由Windows LONGLONG值组成的单个字节吗？

Hi, Could anybody tell me how to access the individual bytes that
consists of a Windows LONGLONG value?

以同样的方式访问任何类型的单个字节。

Same way you access the individual bytes for any type.

shaji写道：

有人可以告诉我如何访问包含Windows LONGLONG值的单个字节？

Hi,
Could anybody tell me how to access the individual bytes that consists
of a Windows LONGLONG value?

可用的解决方案是使用位移：


unsigned char bytes [8]; / * 0最不重要，7最多

重要* /

unsigned long long number;


/ *获得最少有效字节* /

char [0] =数字& 0xff;

/ *获取下一个字节* /

char [1] =（number>> 8）& 0xff;


/ *得到最重要的字节* /

char [7] =（number>> 56）& 0xff;


当然，你可以使用for循环，但我将把它作为一个

练习留给OP。

The protable solution is to use bit shifts:

unsigned char bytes[8]; /* 0 is least significant, 7 is most
significant */
unsigned long long number;

/* get least significant byte */
char[0] = number & 0xff;
/* get next byte */
char[1] = (number >> 8) & 0xff;

/* get most significant byte */
char[7] = (number >> 56) & 0xff;

Of course, you can use a for loop for this but I''m leaving that as an
exercise to the OP.

sl ******* @ yahoo.com schrieb：

shaji写道：

shaji wrote:

有人可以告诉我如何访问包含的单个字节
Windows LONGLONG值？
可用的解决方案是使用位移：

unsigned char bytes [8]; / * 0是最不重要的，7是最重要的* /
无符号长多数;

Hi,
Could anybody tell me how to access the individual bytes that consists
of a Windows LONGLONG value?
The protable solution is to use bit shifts:

unsigned char bytes[8]; /* 0 is least significant, 7 is most
significant */
unsigned long long number;

便携式解决方案可能会读取

unsigned long long number;

unsigned char bytes [sizeof number];
/ *得到最低有效字节* /
char [0] = number& ; 0xff;
/ *获取下一个字节* /
char [1] =（number>> 8）& 0xff;

/ *得到最重要的字节* /
char [7] =（number>> 56）& 0xff;

当然，您可以使用for循环，但我将其作为OP的练习。

The portable solution probably would read
unsigned long long number;
unsigned char bytes[sizeof number];
/* get least significant byte */
char[0] = number & 0xff;
/* get next byte */
char[1] = (number >> 8) & 0xff;

/* get most significant byte */
char[7] = (number >> 56) & 0xff;

Of course, you can use a for loop for this but I''m leaving that as an
exercise to the OP.

循环对于便携式解决方案是必需的。

char [i] =（number>>（i * CHAR_BIT））& （unsigned char）~0UL


干杯

Michael

-

电子邮件：我的是/ at / gmx / dot / de地址。

The loop is necessary for the portable solution.
char[i] = (number >> (i*CHAR_BIT)) & (unsigned char)~0UL

Cheers
Michael
--
E-Mail: Mine is an /at/ gmx /dot/ de address.

这篇关于如何访问LONGLONG值的各个字节的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！