Ajax异步刷新。可能吗 ？ [英] Ajax Asynchronous refresh. Is it possible ?
问题描述
假设我有一个服务器进程，用于监听数据库中的一些更改。
当发生更改时，我想刷新我的页面浏览器通过notyfinig吧。
我不想刷新我的页面，即每5秒，我只想
刷新它只在服务器上更改就像桌面应用程序确实如此。
问题是刷新evry n秒对我的
Web服务器有很大的影响。刷新动作应该只在某些事情真正发生时才有意义
有可能吗？
问候，彼得
Hi,
Say i have a server process which listens for some changes in database.
When a change occurs i want to refresh my page in browser by notyfinig it.
I do not want to refresh my page i.e. every 5 seconds, i just want to
refresh it ONLY on server change just like desktop applications do.
The problem is that refreshing evry n seconds has to much impact on my
web server. The refresh action should be taken only when something
really happens that makes sense
Is it possible ?
greets, peter
推荐答案
我认为这是不可能的，你不能通知一个Web浏览器客户端，它在服务器上发生了变化。这就是网站和网站的性质，它们是无国籍的。
" Piotr Nowak"写道：
I dont think that is possible, you cant "notify" a web browser client that
something has changed on the server. That is the nature of web sites and web
applications, they are "stateless".
"Piotr Nowak" wrote:
假设我有一个服务器进程，可以监听数据库中的一些更改。
当发生变化时，我想通过notyfinig在浏览器中刷新我的页面。
我不想刷新我的页面，即每5秒，我只想
仅在桌面应用程序更新时才刷新服务器。
问题是刷新evry n秒对我的影响很大
网络服务器。刷新动作应该只在某些事情真正发生时才有意义
有可能吗？
greets，peter
Hi,
Say i have a server process which listens for some changes in database.
When a change occurs i want to refresh my page in browser by notyfinig it.
I do not want to refresh my page i.e. every 5 seconds, i just want to
refresh it ONLY on server change just like desktop applications do.
The problem is that refreshing evry n seconds has to much impact on my
web server. The refresh action should be taken only when something
really happens that makes sense
Is it possible ?
greets, peter
NH pisze：
NH pisze:
我不认为这是可能的，你不能"通知"一个Web浏览器客户端，它在服务器上发生了变化。这就是网站和网站的性质，它们是无国籍的。
" Piotr Nowak"写道：
I dont think that is possible, you cant "notify" a web browser client that
something has changed on the server. That is the nature of web sites and web
applications, they are "stateless".
"Piotr Nowak" wrote:
>
说我有一个服务器进程，它会监听数据库中的一些变化。
当一个发生了变化我想在浏览器中通过notyfinig刷新我的页面。
我不想刷新我的页面，即每5秒，我只想刷新它只在服务器更改上就像桌面应用程序一样。
问题是刷新evry n秒对我的网络服务器有很大的影响。刷新动作应该只在真正发生的事情发生时才有意义
是否可能？
greets，peter
>Hi,
Say i have a server process which listens for some changes in database.
When a change occurs i want to refresh my page in browser by notyfinig it.
I do not want to refresh my page i.e. every 5 seconds, i just want to
refresh it ONLY on server change just like desktop applications do.
The problem is that refreshing evry n seconds has to much impact on my
web server. The refresh action should be taken only when something
really happens that makes sense
Is it possible ?
greets, peter
无状态意味着没有关于先前请求的信息在
新的那个，它被遗忘了。
i只想得到一个简单的
更新我的客户端浏览器视图时，从服务器响应。
stateless means that theres no information about previous request in the
new one, its forgotten.
i just want to get one simple response right from the server when
something happens to update my client browser view.
只要有一些asp.net代码就可以了对于正在更新的服务器，运行将返回true或
false，这是可能的。每隔x秒使用ajax
调用，当它返回true时，通过
javascript重新加载页面。
" Piotr诺瓦克" < p。****** @ STRIPTHISwasko.plwrote in message
news：fa ********** @ atlantis.news.tpi.pl ...
As long as there is some asp.net code you can run that will return a true or
false as to the server being updated then this is possible. Use an ajax
call every x seconds and when it returns true issue a page reload via
javascript.
"Piotr Nowak" <p.******@STRIPTHISwasko.plwrote in message
news:fa**********@atlantis.news.tpi.pl...
假设我有一个服务器进程监听数据库中的一些更改。
当发生变化时，我想通过notyfinig在浏览器中刷新我的页面。
我不想刷新我的页面，即每5秒，我只想要
仅在桌面应用程序上更新服务器更新。
问题是令人耳目一新的时间对我的网络有很大的影响
服务器。刷新动作应该只在真正有意义的事情发生时才有意义
有可能吗？
greets，peter
Hi,
Say i have a server process which listens for some changes in database.
When a change occurs i want to refresh my page in browser by notyfinig it.
I do not want to refresh my page i.e. every 5 seconds, i just want to
refresh it ONLY on server change just like desktop applications do.
The problem is that refreshing evry n seconds has to much impact on my web
server. The refresh action should be taken only when something really
happens that makes sense
Is it possible ?
greets, peter
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