128或96位整数类型？ [英] 128 or 96 bit integer types?

问题描述

是否有大型整数类型的内置或第三方支持，例如大小为96或128位的
？我需要如此大尺寸的精度

问题（纳秒）。谢谢。

解决方案

2007年7月27日星期五16:45:05 +0000，Robert Dailey写道：
< blockquote class =post_quotes>
是否有大型整数类型的内置或第三方支持，例如大小为96或128位的
？

是的，只需使用整数值。如果它不适合'int`它

被提升为`long`。 Python`long` \ ns仅限于可用的

内存。


在[59]中：2 ** 128

Out [59]：340282366920938463463374607431768211456L

Ciao，

Marc''BlackJack''Rintsch

Robert Dailey写道：

是否有大型整数类型的内置或第三方支持，例如
为96或128位尺寸？我需要如此大尺寸的精度

问题（纳秒）。谢谢。

>> SECOND = 10 ** 9
年份= 365 * 24 * 60 * 60
2 ** 128 /秒/年

10790283070806014188970L


你在测量什么？宇宙的时代？在纳秒内？


:-)

彼得

7月27日，下午1:27，Peter Otten< __ pete ... @ web.dewrote：

Robert Dailey写道：

是否有大型整数类型的内置或第三方支持，例如
为96或128位大小？我需要如此大尺寸的精度

问题（纳秒）。谢谢。

> SECOND = 10 ** 9
年份= 365 * 24 * 60 * 60
2 ** 128 /秒/年

10790283070806014188970L


你在测量什么？宇宙的时代？在纳秒内？


:-)

嗯，2 ** 96只有2512308552583年。

>

Peter

Hi,

Is there build-in or third party support for large integer types, such
as 96 or 128 bits in size? I require such large sizes for precision
issues (nanoseconds). Thanks.

解决方案

On Fri, 27 Jul 2007 16:45:05 +0000, Robert Dailey wrote:

Is there build-in or third party support for large integer types, such
as 96 or 128 bits in size?

Yes there is, just use integer values. If it don''t fit into an `int` it
gets promoted to a `long`. Python `long`\s are only bounded by available
memory.

In [59]: 2**128
Out[59]: 340282366920938463463374607431768211456L

Ciao,
Marc ''BlackJack'' Rintsch

Robert Dailey wrote:

Is there build-in or third party support for large integer types, such
as 96 or 128 bits in size? I require such large sizes for precision
issues (nanoseconds). Thanks.

>>SECOND = 10**9
YEAR = 365*24*60*60
2**128/SECOND/YEAR

10790283070806014188970L

What are you measuring? The age of the universe? In nanoseconds?

:-)

Peter

On Jul 27, 1:27 pm, Peter Otten <[e-mail]:

Robert Dailey wrote:

Is there build-in or third party support for large integer types, such
as 96 or 128 bits in size? I require such large sizes for precision
issues (nanoseconds). Thanks.

>SECOND = 10**9
YEAR = 365*24*60*60
2**128/SECOND/YEAR

10790283070806014188970L

What are you measuring? The age of the universe? In nanoseconds?

:-)

Well, 2**96 would only be 2512308552583 years.

>
Peter

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