8位整数类型 [英] 8 bit integer type
问题描述
typedef char int（myint8）;
以上是我想做的事情，但当然不能这样做
方式。我四处寻找8位整数类型，但没有运气。
int8_t和simular仍然像chars。
是的我知道这是一个愚蠢的小事，但我厌倦了写作
int（ my8bitvar）;所有的时间，如果有一种类型不起作用的话，我想知道。我想知道。
我还试着定义我自己的类型，但是当我不得不使用
实现所有操作符（==， - =，+ =，+， - ，等等）时，它就丢失了
似乎这是一个非常愚蠢的方式。
所以，请任何人都有答案，让我听听。
问候
typedef char int(myint8);
the above is realy what i wanna do, but ofcourse it cant be done this
way. I have looked around for a 8 bit integer type, but no luck. the
int8_t and simular still acts like chars.
Yes i know it a stupid little thing, but im getting tired of writing
int(my8bitvar); all the time, and if there is a type that doesnt act
like a char, i wanna know.
I have allso tryed defining my own type, but got lost when i had to
implement all the operator (==, -=, +=, ++, --, etc.) and besides it
seemed a really stupid way to go about it.
So please i anyone holds an answer, let me hear it.
Regards
推荐答案
2007-08-29 11:45， za ****** @ gmail.com 写道：
On 2007-08-29 11:45, za******@gmail.com wrote:
typedef char int（myint8）;
以上是我想做的事情，但当然不能这样做
方式。我四处寻找8位整数类型，但没有运气。
int8_t和simular仍然像chars。
是的我知道这是一个愚蠢的小事，但我厌倦了写作
int（ my8bitvar）;所有的时间，如果有一种类型不起作用的话，我想知道。
typedef char int(myint8);
the above is realy what i wanna do, but ofcourse it cant be done this
way. I have looked around for a 8 bit integer type, but no luck. the
int8_t and simular still acts like chars.
Yes i know it a stupid little thing, but im getting tired of writing
int(my8bitvar); all the time, and if there is a type that doesnt act
like a char, i wanna know.
char的行为与int的行为有什么不同，除了它可以容纳的
值范围？
-
Erik Wikstr？m
In what way does a char differ in behaviour from an int, except for the
range of values it can hold?
--
Erik Wikstr?m
8月29日12:25，Erik Wikstr？ m< Erik-wikst ... @ telia.comwrote：
On 29 Aug., 12:25, Erik Wikstr?m <Erik-wikst...@telia.comwrote:
2007-08-29 11:45，zacar ... @ gmail.com写道：
On 2007-08-29 11:45, zacar...@gmail.com wrote:
typedef char int（myint8）;
typedef char int(myint8);
以上是我想做的事情，但当然不能这样做
方式。我四处寻找8位整数类型，但没有运气。
int8_t和simular仍然像chars。
是的我知道这是一个愚蠢的小事，但我厌倦了写作
int（ my8bitvar）;所有的时间，如果有一种类型不起作用的话，我想知道。
the above is realy what i wanna do, but ofcourse it cant be done this
way. I have looked around for a 8 bit integer type, but no luck. the
int8_t and simular still acts like chars.
Yes i know it a stupid little thing, but im getting tired of writing
int(my8bitvar); all the time, and if there is a type that doesnt act
like a char, i wanna know.
char的行为与int的行为有什么不同，除了它可以容纳的
值范围？
-
Erik Wikstr？m
In what way does a char differ in behaviour from an int, except for the
range of values it can hold?
--
Erik Wikstr?m
当然它没什么不同，但确实有所不同，fx。你怎么想？b $ b当我第一次看到stdint.h并且想尝试uint8-t
时发生了什么？
@code
uint8_t var = 7;
std :: cout<< var;
@code
哎呀！它说。
想象一下我的惊讶。和整数类型发出有趣的声音？
是的，它是一个小小的小东西，没人关心，但是
仍然让我不得不写下来
std :: cout<< int（var）;
是的，它只有5个额外的字母，这取决于，但是这个帖子的目标只是为了确保真正的8位整数类型或
一个简单的解决方案并不是全部已经准备好了。
Of course it doesnt differ much, but it does differ, fx. what do you
think happened when i first head about the stdint.h and wanted to try
out the uint8-t?
@code
uint8_t var = 7;
std::cout << var;
@code
BEEP! it said.
Imagine my surprise. and integer type making funny noises?
Yes, it is a tiny little wee wee thing that nobody care about, but
still it enoys me having to write
std::cout << int(var);
Yes, it is only 5 extra letter, well that depends, but the goal of
this post was only to make certain that a real 8 bit integer type or
an easy soluton doesnt allready excist.
2007-08-29 12:35， za ****** @ gmail.com 写道：
On 2007-08-29 12:35, za******@gmail.com wrote:
8月29日，12：25，Erik Wikstr？m< Erik-wikst ... @ telia.comwrote：
On 29 Aug., 12:25, Erik Wikstr?m <Erik-wikst...@telia.comwrote:
> 2007-08-29 11:45，zacar ... @ gmail.com写道：
>On 2007-08-29 11:45, zacar...@gmail.com wrote:
typedef char int（myint8）;
typedef char int(myint8);
以上是我想做的事情，但当然不能这样做
方式。我四处寻找8位整数类型，但没有运气。
int8_t和simular仍然像chars。
是的我知道这是一个愚蠢的小事，但我厌倦了写作
int（ my8bitvar）;所有的时间，如果有一种类型不起作用的话，我想知道。
the above is realy what i wanna do, but ofcourse it cant be done this
way. I have looked around for a 8 bit integer type, but no luck. the
int8_t and simular still acts like chars.
Yes i know it a stupid little thing, but im getting tired of writing
int(my8bitvar); all the time, and if there is a type that doesnt act
like a char, i wanna know.
char的行为与int的行为有什么不同，除了它可以容纳的
值范围？
- Erik Wikstr？m
In what way does a char differ in behaviour from an int, except for the
range of values it can hold?
--
Erik Wikstr?m
当然它没有多大区别，但确实有所不同，fx。你怎么想？b $ b当我第一次看到stdint.h并且想尝试uint8-t
时发生了什么？
@code
uint8_t var = 7;
std :: cout<< var;
@code
哎呀！它说。
想象一下我的惊讶。和整数类型发出有趣的声音？
是的，这是一个小小的小小的东西，没有人关心，但
仍然让我不得不写
std :: cout<< int（var）;
是的，它只有5个额外的字母，这取决于，但是这个帖子的目标只是为了确保真正的8位整数类型或
一个简单的解决方案并不是全部已经准备好了。
Of course it doesnt differ much, but it does differ, fx. what do you
think happened when i first head about the stdint.h and wanted to try
out the uint8-t?
@code
uint8_t var = 7;
std::cout << var;
@code
BEEP! it said.
Imagine my surprise. and integer type making funny noises?
Yes, it is a tiny little wee wee thing that nobody care about, but
still it enoys me having to write
std::cout << int(var);
Yes, it is only 5 extra letter, well that depends, but the goal of
this post was only to make certain that a real 8 bit integer type or
an easy soluton doesnt allready excist.
是的，我明白了。这当然是因为uint8_t只是一个
unsigned char的typedef。我不认为除了编译器供应商或库
供应商可以解决这个问题。
-
Erik Wikstr ？m
Yes, I see. This is of course because uint8_t is just a typedef of an
unsigned char. I don''t think anyone but the compiler vendor or library
vendor can fix this.
--
Erik Wikstr?m
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