内部服务器错误 [英] Internal Server Error
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问题描述
我工作的短信发送应用程序，并为登录目的，我想使用POST方法从我的Android应用程序的Web服务器发送用户名和密码。
当我点击LO-杜松子酒按钮的应用程序没有响应和控制台输出如下消息中的POST请求的响应。
HTTP / 1.1 500内部服务器错误
在运行良好的GET方法我的应用程序。
我无法弄清楚为什么这是造成...
全code是在这里：
包com.vikas.httplogin;
进口java.io.BufferedReader中;
进口java.io.IOException异常;
进口java.io.InputStreamReader中;
进口的java.util.ArrayList;
进口的java.util.List;
进口org.apache.http.Htt presponse;
进口org.apache.http.NameValuePair;
进口org.apache.http.client.ClientProtocolException;
进口org.apache.http.client.HttpClient;
进口org.apache.http.client.entity.UrlEn codedFormEntity;
进口org.apache.http.client.methods.HttpPost;
进口org.apache.http.impl.client.DefaultHttpClient;
进口org.apache.http.message.BasicNameValuePair;
进口android.app.Activity;
进口android.os.Bundle;
进口android.util.Log;
进口android.widget.TextView;
公共类HttpLogin延伸活动{
TextView的电视;
私有静态最后字符串变量=是fatal_error;
/ **第一次创建活动时调用。 * /
@覆盖
公共无效的onCreate（包savedInstanceState）{
super.onCreate（savedInstanceState）;
的setContentView（R.layout.main）;
connecttoServer（）;
}
私人无效connecttoServer（）
{
的BufferedReader BR = NULL;
尝试
{
HttpClient的客户端=新DefaultHttpClient（）;
HttpPost请求=新HttpPost（URL我的网站）;
名单＆LT;的NameValuePair＆GT; PARAMS =新的ArrayList＆LT;的NameValuePair＆GT;（3）;
params.add（新BasicNameValuePair（用户名，vikaspatidar））;
params.add（新BasicNameValuePair（密码，patidar））;
UrlEn codedFormEntity实体=新UrlEn codedFormEntity（PARAMS）;
request.setEntity（实体）;
Log.v（标签，request.getMethod（）的toString（））;
HTT presponse响应= client.execute（要求）;
Log.v（标签，response.getStatusLine（）的toString（））;
BR =新的BufferedReader（新的InputStreamReader（response.getEntity（）的getContent（）））;
StringBuffer的SB =新的StringBuffer（）;
串线=;
串NL = System.getProperty（line.separator）;
而（（行= br.readLine（））！= NULL）{
sb.append（行+ NL）;
}
br.close（）;
字符串结果= sb.toString（）;
Log.v（标签，结果）;
}赶上（ClientProtocolException E）
{
Log.v（标签，e.getMessage（））;
}
赶上（IllegalStateException异常E）{
Log.v（标签，e.getMessage（））;
}赶上（IOException异常E）{
Log.v（标签，e.getMessage（））;
}
}
}
解决方案
下面是解决方案，这样的：
<一个href="http://stackoverflow.com/questions/4470936/how-to-do-a-http-post-in-android/4472300#4472300">How做一个HTTP张贴在Android的？
I am working on an SMS Sending application and for login purpose i want to send the username and password using POST method from my Android Application to the web server.
When I click on lo-gin button the application is not responding and the console prints the following message in response of the Post request.
HTTP/1.1 500 Internal Server Error
While my application running fine with the GET method.
I am not able to figure out why this is causing...
the whole code is here:
package com.vikas.httplogin;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.widget.TextView;
public class HttpLogin extends Activity {
TextView tv;
private static final String tag ="FATAL_ERROR";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
connecttoServer();
}
private void connecttoServer()
{
BufferedReader br = null;
try
{
HttpClient client = new DefaultHttpClient();
HttpPost request = new HttpPost("url of my site");
List<NameValuePair> params = new ArrayList<NameValuePair>(3);
params.add(new BasicNameValuePair("username","vikaspatidar"));
params.add(new BasicNameValuePair("password", "patidar"));
UrlEncodedFormEntity entity = new UrlEncodedFormEntity(params);
request.setEntity(entity);
Log.v(tag,request.getMethod().toString());
HttpResponse response = client.execute(request);
Log.v(tag, response.getStatusLine().toString());
br = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer sb = new StringBuffer("");
String line = "";
String NL = System.getProperty("line.separator");
while ((line = br.readLine()) != null) {
sb.append(line + NL);
}
br.close();
String result = sb.toString();
Log.v(tag, result);
} catch (ClientProtocolException e)
{
Log.v(tag, e.getMessage());
}
catch (IllegalStateException e) {
Log.v(tag, e.getMessage());
} catch (IOException e) {
Log.v(tag, e.getMessage());
}
}
}
解决方案
Here is solution for this:
How to do a HTTP Post in Android?
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