for语句中的多个更新 [英] multiple updates in for statement
问题描述
好的我如何实现:
#define MYCONST 10
for(int i = 0; i< MYCONST; i ++, j--)
{
}
这是我想在for语句的最后部分有两个项目。
谢谢
迈克
Ok how do i implement:
#define MYCONST 10
for(int i=0;i<MYCONST;i++,j--)
{
}
that is I want two items in the last part of the for statement.
Thanks
Mike
推荐答案
" Michael" < SL *********** @ hotmail.com>在消息中写道
news:c8 ********** @ hercules.btinternet.com ...
"Michael" <sl***********@hotmail.com> wrote in message
news:c8**********@hercules.btinternet.com...
好我如何实施:
#define MYCONST 10
for(int i = 0; i< MYCONST; i ++,j--)
{
}
这就是我想在for语句的最后部分有两个项目。
谢谢
Mike
Ok how do i implement:
#define MYCONST 10
for(int i=0;i<MYCONST;i++,j--)
{
}
that is I want two items in the last part of the for statement.
Thanks
Mike
我什么也看不见你发布了什么错了。当你编译/运行它时会发生什么?
john
I don''t see anything wrong with what you''ve posted. What happens when you
compile/run it?
john
Michael写道:
Michael wrote:
好我该如何实现:
#define MYCONST 10
for(int i = 0; i< MYCONST; i ++,j - )
{
}
Ok how do i implement:
#define MYCONST 10
for(int i=0;i<MYCONST;i++,j--)
{
}
你的实施是对的。
我不明白你在问什么...
- Dario
Your implementation is right.
I do not understand what are you asking...
- Dario
" Michael" < SL *********** @ hotmail.com>在消息中写道
news:c8 ********** @ hercules.btinternet.com ...
"Michael" <sl***********@hotmail.com> wrote in message
news:c8**********@hercules.btinternet.com...
好我如何实施:
#define MYCONST 10
for(int i = 0; i< MYCONST; i ++,j--)
{
}
这就是我想在for语句的最后一部分中有两个项目。
Ok how do i implement:
#define MYCONST 10
for(int i=0;i<MYCONST;i++,j--)
{
}
that is I want two items in the last part of the for statement.
假设j在某处被定义,你就没事了。如果不是 :
for(int i = 0,j = MYCONST; i!= MYCONST; ++ i, - j)
{
}
Jeff F
Assuming j is defined somewhere, you''re fine as is. If not how about:
for( int i = 0, j = MYCONST ; i != MYCONST ; ++i, --j )
{
}
Jeff F
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