for语句中有多个条件 [英] Multiple conditions in for statement

问题描述

我在函数中有这个代码，但是当它运行时，它会长时间暂停，然后它说：

I have this code in a function, but when it runs it does a long pause and then it says:

$floating point exception

我假设这是由于for循环中的多个条件，知道为什么它是错的。任何想法？

I am assuming this is due to multiple conditions in the for loop, but I don't know why it is wrong. Any ideas?

int i,j,number=5;
for (i = 2; (i < number || j==1); i++)
{
    if (number%i==0)
    {
        j = 1;
    }
}

推荐答案

strong>浮点异常 - 这意味着有一个算术错误。

floating point exception - This means there's an arithmetic error.

看起来你想用j停止循环， （因为一旦你得到 j == 1 ，或条件总是 true ）。

然后发生的是你通过整数值回到 0 并获取异常，循环 i 。

It looks like you're trying to stop the loop with j, but what you're actually doing is continuing the loop forever (because once you get j==1 the or condition is always true).
What then happens is you loop i through all the Integer values back to 0 and get the exception.

我想你想做的是：

for (i = 2; (i < number); i++)
{
    if (number%i==0)
    {
        j = 1;
        break;
    }
}

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