如何重新present 2光标为1排序光标？ [英] How to represent 2 cursors as 1 sorted cursor?

问题描述

我有2个不同的数据集，他们每个人用自己的的ContentProvider 。查询到他们，我可以得到2个不同的游标。这些2光标有2个不同的主键，但有一个相同的字段（ DATE ），我可以使用排序（其它领域是不同的）。

I have 2 different sets of data, each of them use its own ContentProvider. Querying to them I can get 2 different cursors. Those 2 cursors has 2 different primary keys, but there's one and the same field (DATE) which I can use for ordering (other fields are different).

我的目标是有一个最终的合并光标这将是由那些 DATE 字段进行排序。我已经调查 MergeCursor ，但它不适合我，因为它返回的合并/连接起来（但没有排序光标 ）。

My goal is to have one final merged Cursor which will be sorted by those DATE field. I have investigated MergeCursor but it doesn't fit to me, since it returns merged/concatenated (but not sorted Cursor).

任何想法，线索？

推荐答案

您可以试试这个类从AOSP版本库：<一href="https://android.googlesource.com/platform/frameworks/base.git/+/android-4.4.4_r1/core/java/com/android/internal/database/SortCursor.java" rel="nofollow">https://android.googlesource.com/platform/frameworks/base.git/+/android-4.4.4_r1/core/java/com/android/internal/database/SortCursor.java

You can try this class from AOSP repository: https://android.googlesource.com/platform/frameworks/base.git/+/android-4.4.4_r1/core/java/com/android/internal/database/SortCursor.java

有一个性能警告在类的开始，但如果你没有10K或100K的记录可能被罚款。

There is a performance warning at the beginning of the class but if you don't have 10K or 100K records it might be fine.

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