在Python中嵌套if中的元素 [英] Counting elements in nested if in Python

问题描述

我想创建一个程序，可以打印超过3人观看的电影数量（存储在嵌套列表中的数据如下）。



list_movies = [（'Spiderman 3'，['John'，'jake'，'Ronald']），（'Gravity'，['james'，'jake'，'john'，'gerald']），

（'终结者'，['安妮'，'约翰尼'，'彼得'，'罗纳德'，'内维尔'）]



我的尝试：

I want to create a program that can print the number of movies that was watched by more than 3 people(data stored in a nested list as below ).

list_movies = [('Spiderman 3', ['John', 'jake','Ronald']),('Gravity',['james','jake','john','gerald']),
('Terminator',['Anne','Johnny','Peter','Ronald','Neville'])]

What I have tried:

list_movies = [('Spiderman 3', ['John', 'jake','Ronald']),('Gravity',['james','jake','john','gerald']),
               ('Terminator',['Anne','Johnny','Peter','Ronald','Neville'])]



count2 = 0
for (movie,name) in list_movies:
    count = 0
    for (name) in list_movies:
        if name != '':
            count += 1
    if count > 3:
        count2 += 1
    
print(count)
print(count2)

推荐答案

你的内部循环应该遍历元组的第二项：

You inner loop should iterate over the second item of the tuple:

list_movies = [('Spiderman 3', ['John', 'jake','Ronald']),('Gravity',['james','jake','john','gerald']),
               ('Terminator',['Anne','Johnny','Peter','Ronald','Neville'])]



count2 = 0
for (movie,viewers) in list_movies:
    count = 0
    for (name) in viewers:
        if name != '':
            count += 1
    if count > 3:
        count2 += 1

print("last movie viewers: %d" % count)
print("count of movies having had more than three viewers: %d" % count2)

这篇关于在Python中嵌套if中的元素的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！