如何在直线上移动角色？ [英] How to move a character on straight line?

问题描述

我必须在c ++上创建一个简单的编码项目。我需要在y = mx + c中移动*字符。我写了一杯编码线来生成直线。现在我必须在这条道路上移动它。 PLZ帮助我.....



我尝试过：

I have to make a simple coding project on c++. i need to move "*" character in y=mx+c. i wrote a cup of coding lines to generate straight lines. now i have to move this in that path. plz help me.....

What I have tried:

#include <iostream>
#include <math.h>
#include<Windows.h>
using namespace std;

int pth (int x)  {
    return -1*x+1;
}

int main()  {
    int i,j,y;
    for (int x=-10;x <= 10;x++)  {
        for ( i=-10;i <= x;i++)  {
            if (i==x) {
                y=pth(x);
               // cout<<"x=";
                //cout<<x;
                //cout<<"y=";
                //cout<<y;

                for(j=-10;j<=y;j++) {
                   if(j==y)
                        cout << "*";
                    else
                        cout << " ";
                }
            }
        }
        cout << "\n";
system("cls");
Sleep(20);
    }
    cin.get();
    return 0;
 }

推荐答案

简单：更改 pth 函数以便使用新公式而不是 -1 * x + 1 - 这是的特殊情况y = mx + c 其中m == -1，c == 1

Simple: Change your pth function to use the new formula instead of -1*x+1 - which is a special case of y = mx + c where m == -1, and c == 1

可能你需要使用 Windows控制台API [ ^ ]。

Probably you need to use the Windows Console API[^].

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