JavaScript中的Prototypal继承......我可以称之为“超级”吗？当量？ [英] Prototypal Inheritance in JavaScript...Can I call a "super" equivalent?

问题描述

我正在使用原型继承在javascript中构建面向对象的库。与Java和.NET类似，我的所有对象/原型都将继承Object对象/原型。我想知道是否可以从派生函数中调用超级对象/原型函数？

I am building an object oriented library in javascript using prototypal inheritance. Similarly to Java and .NET, all of my objects/prototypes will inherit the "Object" object/prototype. I want to know if it is possible to call super object/prototype functions from derived ones?

考虑下面的代码例子：

function Object() {
    this.DoAction = function() {
    };
};

function CustomObject() {
    this.DoAction = function() {
        super.DoAction();    //How do I do this in JavaScript?
    };
};

推荐答案

JavaScript没有直接相当于 super 。

JavaScript does not have the direct equivalent of super.

解决方法可能是在覆盖原型之前将方法保存在原型上，例如：

A workaround could be to save the method on the prototype before overriding it, like:

function CustomObject() {
    this._super_DoAction = this.DoAction;
    this.DoAction = function() {
        this._super_DoAction(); 
    };
};

如果您能够使用ES5功能，则可以使用 Object.getPrototypeOf 从原型中获取方法，然后应用以当前对象执行它 this ：

If you are able to use ES5 features, you can use Object.getPrototypeOf to get the method from the prototype, and then apply to execute it with the current object as this:

function CustomObject(){
    this.DoAction=function() {
        Object.getPrototypeOf(this).DoAction.apply(this, []);
    };
}

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