添加输出不正确 [英] The addition output is not correct

问题描述

＃包括< stdio.h中> 
 main（）
 {
 int a，b，c = a + b; 
 printf（输入a \ n的值）; 
 scanf（％d，& a）; 
 printf（输入b\ n的值）; 
 scanf（％d，& b）; 
 printf（a + b =％d，c）; 
 system（暂停）; 
} 

我的尝试：



我尝试使用不同的输入，但输出显示1总是针对不同的输入

解决方案

代码与您编写时一样工作。



发生的事情是您定义了变量a，b和c。变量a和b没有值，但应该是0.你告诉编译器将a和b加在一起并将结果赋给c。



Wellllllll，that代码只能工作一次。你并没有告诉编译器使用它作为一个公式，说这就是你总是如何确定c的值。没有在C或我知道的任何其他语言中定义这样的公式。



你必须运行代码才能在你之后进行计算从用户那里得到a和b的值。

  int  a，b，c; 
  //  获取a和b的值...  
c = a + b; 
  //  显示结果...  
 

与浮点变量的输出为0.0000 [ ^ ]

好悲伤，但你学习速度慢...

与上一个问题相同，双引号位于错误的位置。改变这个：

 scanf（％d，& b）; 

对此：

 scanf（％d，& b）; 

并尝试记住这一次！ ：笑：

#include<stdio.h>
main()
{
	int a,b,c=a+b;
	printf("Enter the value for a\n");
	scanf("%d, &a");
	printf("Enter the value for b\n");
	scanf("%d, &b");
	printf("a+b=%d", c);
	system ("pause");
}

What I have tried:

I tried with different inputs but the output is showing 1 always for different inputs

解决方案

The code works as you wrote it.

What is happening is that you defined the variables a, b, and c. The variables a and b have no values, but should be 0. You told the compiler to add a and b together and assign the result to c.

Wellllllll, that code only works once. You're NOT telling the compiler to use this as a formula that say "this is how you always determine the value of c". There is no such thing as defining a formula like this in C, or any other language that I know of.

You have to run code that makes that calculation AFTER you get the values of a and b from the user.

int a, b, c;
// Get the values for a and b...
c = a + b;
// Show the result...

Exactly the same error on your part as The output for float variable is 0.0000[^]

Good grief, but you are a slow learner...
Same as your last question, the double quotes are in the wrong place. Change this:

scanf("%d, &b");

To this:

scanf("%d", &b);

And try to remember this time! :laugh:

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