输出不正确 [英] Output incorrect
本文介绍了输出不正确的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
当我进行d-c + a + b之类的不同组合时，它给出的数字不正确，例如118.0.有人可以告诉我我的代码在哪里错误.. 谢谢
ValVarPairs.txt包含以下数字-> a = 100，b = 5，c = 10，d = 13 这就是我编写的代码.
package com.ecsgrid;
import java.io.*;
public class testC {
public static void main(String[] args) {
int i = 0,j = 0;
double result, values[] = new double[4];
char k, operators[] = new char[3];
for (i = 0; i <= 2; i++)
operators[i] = '+'; // default is to add the values
File myfile;
StreamTokenizer tok;
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
String InputText;
i = 0;
try {
myfile = new File("C:\\VarValPairs.txt");
tok = new StreamTokenizer(new FileReader(myfile));
tok.eolIsSignificant(false);
while ((tok.nextToken() != StreamTokenizer.TT_EOF) && (i <= 3)){
if ((tok.ttype == StreamTokenizer.TT_NUMBER))
values[i++] = tok.nval;
}
}
catch(FileNotFoundException e) { System.err.println(e); return; }
catch(IOException f) { System.out.println(f); return; }
System.out.println("Enter letters and operators:");
try {
InputText = in.readLine();
}
catch(IOException f) { System.out.println(f); return; }
for (i = 0; i < InputText.length(); i++)
{
k = InputText.charAt(i);
if ((k == '+') || (k == '-'))
{
if (j <= 2) operators[j++] = k;
}
}
result = values[0];
for (i = 0; i <= 2; i++){
if (operators[i] == '+')
result = result + values[i+1];
else
result = result - values[i+1];
}
System.out.println(result);
}
}
解决方案
让我们调试一下，添加一些系统输出...
这是您在每个步骤中看到的内容 100.0-5.0 95.0 + 10.0 105.0 + 13.0 118.0
您的值数组为{100,5,10,13}，而您的运算符数组为{-，+，+}
您尚未映射a = 100，b = 5，c = 10，d = 13，除非您进行映射，然后使用基于非操作数输入键的映射来解析操作数，否则它将无法正常工作. /p>
因此，如果我要使用字符的int值，则可以通过这种方式进行翻译.
import java.io.*;
public class TestC {
public static void main(String[] args) {
int i = 0, j = 0;
double result, values[] = new double[4];
char k, operatorsAndOperands[] = new char[3];
for (i = 0; i <= 2; i++)
operatorsAndOperands[i] = '+'; // default is to add the values
File myfile;
StreamTokenizer tok;
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
String InputText;
i = 0;
try {
myfile = new File("C:\\VarValPairs.txt");
tok = new StreamTokenizer(new FileReader(myfile));
tok.eolIsSignificant(false);
while ((tok.nextToken() != StreamTokenizer.TT_EOF) && (i <= 3)) {
if ((tok.ttype == StreamTokenizer.TT_NUMBER))
values[i++] = tok.nval;
}
for (int l = 0; l < values.length; l++) {
System.out.println(values[l]);
}
} catch (FileNotFoundException e) {
System.err.println(e);
return;
} catch (IOException f) {
System.out.println(f);
return;
}
System.out.println("Enter letters and operators:");
try {
InputText = in.readLine().toUpperCase();
} catch (IOException f) {
System.out.println(f);
return;
}
if(InputText.length() > 0){
operatorsAndOperands = new char[InputText.length()];
} else {
System.out.println("No Operations specified");
return;
}
for (i = 0; i < InputText.length(); i++) {
k = InputText.charAt(i);
operatorsAndOperands[j++] = k;
}
result = 0;
for (i = 0; i < operatorsAndOperands.length; i++) {
System.out.println(operatorsAndOperands[i] + " " + (int)operatorsAndOperands[i]);
if(i+1<operatorsAndOperands.length)
System.out.println(operatorsAndOperands[i+1]);
switch(operatorsAndOperands[i]){
case '+':
if(operatorsAndOperands[i+1] != '+' && operatorsAndOperands[i+1] != '-'){
result+=values[(int)operatorsAndOperands[i+1] - (int)'A'];
i++;
}
break;
case '-':
if(operatorsAndOperands[i+1] != '+' && operatorsAndOperands[i+1] != '-'){
result-=values[(int)operatorsAndOperands[i+1] - (int)'A'];
i++;
}
break;
default:
result = values[(int)operatorsAndOperands[i] - (int)'A'];
break;
};
System.out.println(result);
}
System.out.println(result);
}
}
When I do different combinations like d-c+a+b it gives me a inccorect number like 118.0. Can someone tell me where in my code my calculations are wrong.. Thank you
the ValVarPairs.txt contains these numbers-> a=100,b=5,c=10,d=13 This is what i coded.
package com.ecsgrid;
import java.io.*;
public class testC {
public static void main(String[] args) {
int i = 0,j = 0;
double result, values[] = new double[4];
char k, operators[] = new char[3];
for (i = 0; i <= 2; i++)
operators[i] = '+'; // default is to add the values
File myfile;
StreamTokenizer tok;
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
String InputText;
i = 0;
try {
myfile = new File("C:\\VarValPairs.txt");
tok = new StreamTokenizer(new FileReader(myfile));
tok.eolIsSignificant(false);
while ((tok.nextToken() != StreamTokenizer.TT_EOF) && (i <= 3)){
if ((tok.ttype == StreamTokenizer.TT_NUMBER))
values[i++] = tok.nval;
}
}
catch(FileNotFoundException e) { System.err.println(e); return; }
catch(IOException f) { System.out.println(f); return; }
System.out.println("Enter letters and operators:");
try {
InputText = in.readLine();
}
catch(IOException f) { System.out.println(f); return; }
for (i = 0; i < InputText.length(); i++)
{
k = InputText.charAt(i);
if ((k == '+') || (k == '-'))
{
if (j <= 2) operators[j++] = k;
}
}
result = values[0];
for (i = 0; i <= 2; i++){
if (operators[i] == '+')
result = result + values[i+1];
else
result = result - values[i+1];
}
System.out.println(result);
}
}
解决方案
Let's debug this a little, add a few system outs...
this is what you would see for each step 100.0 - 5.0 95.0 + 10.0 105.0 + 13.0 118.0
your value array is {100,5,10,13} and your operator array is {-,+,+}
you have not mapped a = 100, b = 5, c= 10, d = 13, unless you map those then parse the operands using the mapping based on the non operand input keys, it is not going to work.
So, if I were to use the character's int values, I would be able to translate it this way.
import java.io.*;
public class TestC {
public static void main(String[] args) {
int i = 0, j = 0;
double result, values[] = new double[4];
char k, operatorsAndOperands[] = new char[3];
for (i = 0; i <= 2; i++)
operatorsAndOperands[i] = '+'; // default is to add the values
File myfile;
StreamTokenizer tok;
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
String InputText;
i = 0;
try {
myfile = new File("C:\\VarValPairs.txt");
tok = new StreamTokenizer(new FileReader(myfile));
tok.eolIsSignificant(false);
while ((tok.nextToken() != StreamTokenizer.TT_EOF) && (i <= 3)) {
if ((tok.ttype == StreamTokenizer.TT_NUMBER))
values[i++] = tok.nval;
}
for (int l = 0; l < values.length; l++) {
System.out.println(values[l]);
}
} catch (FileNotFoundException e) {
System.err.println(e);
return;
} catch (IOException f) {
System.out.println(f);
return;
}
System.out.println("Enter letters and operators:");
try {
InputText = in.readLine().toUpperCase();
} catch (IOException f) {
System.out.println(f);
return;
}
if(InputText.length() > 0){
operatorsAndOperands = new char[InputText.length()];
} else {
System.out.println("No Operations specified");
return;
}
for (i = 0; i < InputText.length(); i++) {
k = InputText.charAt(i);
operatorsAndOperands[j++] = k;
}
result = 0;
for (i = 0; i < operatorsAndOperands.length; i++) {
System.out.println(operatorsAndOperands[i] + " " + (int)operatorsAndOperands[i]);
if(i+1<operatorsAndOperands.length)
System.out.println(operatorsAndOperands[i+1]);
switch(operatorsAndOperands[i]){
case '+':
if(operatorsAndOperands[i+1] != '+' && operatorsAndOperands[i+1] != '-'){
result+=values[(int)operatorsAndOperands[i+1] - (int)'A'];
i++;
}
break;
case '-':
if(operatorsAndOperands[i+1] != '+' && operatorsAndOperands[i+1] != '-'){
result-=values[(int)operatorsAndOperands[i+1] - (int)'A'];
i++;
}
break;
default:
result = values[(int)operatorsAndOperands[i] - (int)'A'];
break;
};
System.out.println(result);
}
System.out.println(result);
}
}
这篇关于输出不正确的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
查看全文
