使用list（）的语法错误 [英] Syntax error using list()

问题描述

我在PHP中使用list功能似乎有语法问题。在下面的代码中，我试图使用一行代码将两个数组值转换为两个单独的变量。我知道这可以用一个简单的变量。我可以在两条单独的线上成功完成 - 按照线路评论工作就好了。

可以somone请协助正确的suntax线： -

list （$ outlying，$ base）=（array（$ row ['outlying_price'] ['base_price']））;

因此行返回以下错误： -



警告：第19行的C：\ wamp64 \\\test.php中的非法字符串偏移'base_price'

注意：未定义的偏移：C中为1 ：第19行：\ wamp64 \\\test.php



我尝试过：

I appear to have a syntax problem using the list feature in PHP. In the code below I am trying to convert two array values into two seperate variables, using one line of code. I know this is possible with a simple variable. I can do it successfully on two seperate lines - as per the lines commented out work just fine.
Can somone please assist with the correct suntax for the line :-
list($outlying, $base) = (array($row['outlying_price'] ['base_price']));
as this line returns the following error:-

Warning: Illegal string offset 'base_price' in C:\wamp64\www\test.php on line 19
Notice: Undefined offset: 1 in C:\wamp64\www\test.php on line 19

What I have tried:

<?php

			include 'database.php';
			$pdo = Database::connect();
			try{
			$collhub = "bet";
			$delhub = "jnb";
			echo $collhub;
			echo $delhub;
			echo "<br>";
			$sql = "SELECT * FROM `new_ice_price_table` WHERE collection_town_code = '$collhub' AND delivery_town_code = '$delhub'";
			$result = $pdo->query($sql);
						if($result->rowCount() > 0){
						//echo "<table class='table table-striped table-bordered sortable'>";
						while($row = $result->fetch()){
						//print_r($row);
						//list($base) = array($row['base_price']);
						//list($outlying) = array($row['outlying_price']);
						list($outlying, $base) = (array($row['outlying_price'] ['base_price']));
						echo "<br>";
						echo $base;
						echo "<br>";
						echo $outlying;
					}
						echo "</table></br>";

						unset($result);
					} else{
						echo "No records matching your query were found.";
					}
					} catch(PDOException $e){
					die("ERROR: Could not able to execute $sql. " . $e->getMessage());
		}			
	?>

推荐答案

outlying，

base ）=（array（

base) = (array(

row ['outlying_price'] ['base_price']））;

，因为此行返回以下错误： -



警告：第19行C：\ wamp64 \\\test.php中的非法字符串偏移'base_price'

注意：未定义的偏移量：C中的1：第19行的\ wamp64 \\\\\ test.php



我的尝试：

row['outlying_price'] ['base_price']));
as this line returns the following error:-

Warning: Illegal string offset 'base_price' in C:\wamp64\www\test.php on line 19
Notice: Undefined offset: 1 in C:\wamp64\www\test.php on line 19

What I have tried:

<?php

			include 'database.php';

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