警告:mysql_fetch_array()要求参数1为resource,boolean给出 [英] Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in
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问题描述
警告:mysql_fetch_array()期望参数1为资源,布局在第135行的/storage/ssd1/632/6410632/public_html/Admin/User.php中给出。
警告:mysql_num_rows()期望参数1为资源,布线在第150行的/storage/ssd1/632/6410632/public_html/Admin/User.php中给出
我尝试过:
< pre> //指定要执行的查询
$ sql =select * from User_Master;
//执行查询
$ result = mysql_query($ sql,$ con);
//遍历每个记录
while($ row = mysql_fetch_array($ result))
{
$ Id = $ row ['UserId'];
$ UserName = $ row ['UserName'];< / pre>
解决方案
sql =select * from User_Master;
//执行查询
result = mysql_query(
SQL,
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /storage/ssd1/632/6410632/public_html/Admin/User.php on line 135 Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in /storage/ssd1/632/6410632/public_html/Admin/User.php on line 150
What I have tried:
<pre>// Specify the query to execute
$sql = "select * from User_Master";
// Execute query
$result = mysql_query($sql,$con);
// Loop through each records
while($row = mysql_fetch_array($result))
{
$Id=$row['UserId'];
$UserName=$row['UserName'];</pre>
解决方案
sql = "select * from User_Master";
// Execute query
result = mysql_query(
sql,
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