如何获取程序的指定输出？ [英] How do I get the specified output for my program?
问题描述
读取输入数字（比如n）并计算表达式n + nn + nnn的值的Java程序？
我用5号试过它，预期输出应该是5 + 55 + 555 = 615。但输出是7320.请检查我的代码并建议任何更正。
谢谢。
我尝试过：
import java.util.Scanner;
public class Formula {
public static void main（String [] args）{
// TODO自动生成的方法存根
扫描仪输入=新扫描仪（System.in）;
System.out.print（输入数字：）;
int n = in.nextInt （）;
int sum = 0;
for（int i = 0; i< = 3; i ++）{
sum = sum + n;
n = n * 11;
}
System.out.print（sum）;
}
}
A Java Program that reads an input digit (say n) and computes the value of the expression n+nn+nnn ?
I have tried it with number 5 and the expected output should be 5+55+555=615. But the output was 7320. Please check my code and suggest any corrections.
Thanks.
What I have tried:
import java.util.Scanner;
public class Formula {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner in = new Scanner(System.in);
System.out.print("Input number : ");
int n = in.nextInt();
int sum=0;
for(int i=0 ; i<=3 ; i++) {
sum = sum+n;
n=n*11;
}
System.out.print(sum);
}
}
推荐答案
尝试使用调试器查看程序中发生了什么。你会看到发生了以下情况：
迭代1：n = 5
迭代2：n = 5 * 11 = 55
迭代3：n = 55 * 11 = 605
迭代4：n = 605 * 11 = 6655
sum = 5 + 55 + 605 + 6655 = 7320
Try use the debugger to see what's going on in your program. You'll see what's happening is the following:
Iteration 1: n = 5
Iteration 2: n = 5*11 = 55
Iteration 3: n = 55*11 = 605
Iteration 4: n = 605*11 = 6655
sum = 5 + 55 + 605 + 6655 = 7320
这篇关于如何获取程序的指定输出？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
