指定cython输出文件 [英] Specify cython output file

问题描述

似乎默认情况下，从distutils.core中将cmdclass设置为build_ext的安装程序编译当前工作目录中的cpp或c文件。有没有一种方法可以确定将生成的c代码写入何处？否则，存储库中会堆满生成的代码。

It seems that by default setup from distutils.core with cmdclass set to build_ext, compiles a cpp or c file in the current working directory. Is there a way to determine where the generated c code is written to? Otherwise, a repository will be littered with generated code.

例如，此文件setup.py会将文件example.c写入当前工作目录：

For example this file setup.py will write a file example.c to the current working directory:

from distutils.core import setup
from Cython.Build import cythonize

setup(
      ext_modules = cythonize("example.pyx"))

推荐答案

您可以将选项 build_dir =目录名称 传递给 Cythonize

# rest of file as before
setup(
      ext_modules = cythonize("example.pyx",
                              build_dir="build"))

上面的代码会将生成的c文件放在目录 build中（这很有意义，因为

The above code will put the generated c files in the directory "build" (which makes sense, since by default it's where distutils puts temporary object files and so forth when it's building).

我的原始答案是工作，而不是 build_dir 。感谢@ArthurTacca指出这似乎不再正确。

My original answer had working, not build_dir. Thanks to @ArthurTacca for pointing out that that no longer seems to be right.

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