你好，我有一个问题。如何通过用户输入找到删除键的ascii值 [英] Hello I have a question. How can I find the ascii value of the delete key by user input

问题描述

我需要通过用户输入或cin获取删除键的ascii值。



我尝试过：



我知道删除键的ascii值为127.

我也可以通过以下方式获得：

static_cast< ; int>（'/ x7f'）或类似的序列，但我需要通过用户输入获取它。我怎么能这样做？

I need to get the ascii value of delete key by user input or cin.

What I have tried:

I know the delete key has an ascii value of 127.
I can also get this by using:
static_cast<int>('/x7f') or some similar sequence, but i need to get it via user input. How can i do that?

推荐答案

我记得在大学期间我们曾经做过类似的事情，因为我不再使用C ++了。检查是否有帮助 -

I remember we used to do something like following during college days as I no more use C++. Check if it helps-

char c;
c=getch();
cout << "Code for key pressed" << c;

希望，它有帮助：）

Hope, it helps :)

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