如何通过键或值删除用户? [英] How do I remove a user by key or value?

问题描述

我的 Firebase 数据库中有这样的结构:

I have a structure in my Firebase database like this:

--users
    --v7BwBnUBqJMXCtoOHYE51jXCwhY2: uid
    --etc

当用户像这样通过身份验证时，用户表"会被填充:

The users 'table' gets populated when a user gets authenticated like this:

  loginFb() {
    this.af.auth.login({
      provider: AuthProviders.Facebook,
      method: AuthMethods.Popup,
    }).then(
        (user) => {
        this.userOnline(user.uid, 'uid');
        this.router.navigate(['/members']);
      }).catch(
        (err) => {
        this.error = err;
      })
  }

  userOnline(uid, value) {
    const users = this.af.database.object('/users');
    users.update({ [uid]: value });
  }

这会在 fb 生成的用户表中为 ea 用户提供一个 uid.

This gives ea user a uid in the user table thats generated by fb.

我想在用户注销时删除用户.研究这个我遇到了这个答案.

I want to remove the user when they logout. Researching this I have come across this answer.

我是这样应用的:

  logout(userUID) {
    this.af.auth.logout();
    this.userOffline(userUID);
    this.router.navigateByUrl('/login');
  }

  userOffline(userUID) {

    const user = this.af.database.list('/', {
      query: {
        orderByChild: userUID,
        equalTo: 'uid'
      }
    });

    user.subscribe(snapshots=>{
      snapshots.forEach(snapshot => {
        console.log(snapshot);
        snapshot.ref.remove();
      });
    })

  }

console.log 的结果是:

The result of the console.log is:

Object {v7BwBnUBqJMXCtoOHYE51jXCwhY2: "uid", $key: "users"}

唉，我收到这个错误:

Cannot read property 'remove' of undefined

我确信有更好的方法可以做到这一点，但我找不到任何东西.任何建议表示赞赏.

I'm sure there is a better way to do this but I couldn't find anything. Any advice is appreciated.

编辑

感谢@pengyy 的评论，我对他们的建议做了一个小修改.

Thanks to @pengyy comment I made a minor amend to their suggestion.

user.subscribe(snapshots=>{
  snapshots.forEach(snapshot => {
    console.log(snapshot);
    this.af.database.list('/users').remove(snapshot.userUID)
  });
})

这有效并删除了用户，但它会在页面加载时立即执行，即使调用该函数时也不会......绘图变厚

This works and removes the user but it does so straight away on page load not even when the function is called... the plot thickens

推荐答案

  userOffline(userUID) {
    this.af.database.list('/users/'+userUID).remove();
  }

所以这是有效的.这么简单...

So this works. So simple...

谢谢@pengyy 如果没有您的评论，我就不会到达那里.

Thanks @pengyy I wouldn't have got there without your comments.

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