如何删除键并从PHP数组返回值? [英] How to delete a key and return the value from a PHP array?

问题描述

使用PHP时，我发现自己经常写这样的代码:

When using PHP, I find myself writing code like this a lot:

$target = $_SESSION[AFTER_LOGIN_TARGET];
unset($_SESSION[AFTER_LOGIN_TARGET]);
return $target;

在Python中，有一个dict.pop方法可以让我在一个语句中执行类似的操作，而无需使用临时变量:

In Python, there is a dict.pop method that would let me do something similar in one statement, without a temporary variable:

return session.pop(AFTER_LOGIN_TARGET)

PHP中是否有类似的功能或技巧?

Is there a similar function or trick in PHP?

推荐答案

我没有看到内置函数，但是您可以轻松创建自己的函数.

I don't see a built-in function for this, but you can easily create your own.

/**
 * Removes an item from the array and returns its value.
 *
 * @param array $arr The input array
 * @param $key The key pointing to the desired value
 * @return The value mapped to $key or null if none
 */
function array_remove(array &$arr, $key) {
    if (array_key_exists($key, $arr)) {
        $val = $arr[$key];
        unset($arr[$key]);

        return $val;
    }

    return null;
}

您可以将其用于任何数组，例如$_SESSION:

You can use it with any array, e.g. $_SESSION:

return array_remove($_SESSION, 'AFTER_LOGIN_TARGET');

又甜又甜

在PHP 7+中，您可以使用空合并运算符可大大缩短此功能.您甚至不需要isset()！

With PHP 7+ you can use the null coalescing operator to shorten this function greatly. You don't even need isset()!

function array_remove(array &$arr, $key) {
    $val = $arr[$key] ?? null;
    unset($arr[$key]);
    return $val;
}

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