如何在ENDLOCAL中返回值数组 [英] How to return an array of values across ENDLOCAL
本文介绍了如何在ENDLOCAL中返回值数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有两个可变长度的值数组,TargetName []和TargetCpu [],我需要跨越ENDLOCAL边界返回它们.我尝试了以下操作,但是仅返回第一个数组的第一个值.
I have two variable length arrays of values, TargetName[] and TargetCpu[], which I need to return across the ENDLOCAL boundary. I've tried the following, but only the first value on the first array gets returned.
for /L %%i in (0,1,%MaxIndex%) do (
for /f "delims=" %%j in (""!TargetName[%%i]!"") do (
for /f "delims=" %%k in (""!TargetCpu[%%i]!"") do (
endlocal
set TargetName[%%i]=%%j
set TargetCpu[%%i]=%%k
)
)
)
下面是返回值的打印.
Number Targets: 3
TargetName[0]: "Computer1"
TargetCpu[0] : "x64"
TargetName[1]: "!TargetName[1]!"
TargetCpu[1] : "!TargetCpu[1]!"
TargetName[2]: "!TargetName[2]!"
TargetCpu[2] : "!TargetCpu[2]!"
我已经了解了所有可以找到的内容,但是我尝试过的任何方法都不能用于可变长度数组.
I've read about everything I can find, but nothing I've tried works for a variable length array.
推荐答案
@echo off
setlocal
set "MaxIndex=6"
call :CreateArrays
set TargetName
set TargetCPU
goto :EOF
:CreateArrays
setlocal EnableDelayedExpansion
for /L %%i in (1,1,%MaxIndex%) do (
set /A TargetName[%%i]=!random!, TargetCpu[%%i]=!random!
)
rem Return the arrays to the calling scope
set "currentScope=1"
for /F "delims=" %%a in ('set TargetName[ ^& set TargetCPU[') do (
if defined currentScope endlocal
set "%%a"
)
exit /B
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