使用servlet-hibernateintegration的分页概念。 [英] Pagination concept using servlet-hibernateintegration.

问题描述

@WebServlet("/PagenationServlet") 
public class PagenationServlet extends HttpServlet {

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException 
{
    response.setContentType("text/html");
    PrintWriter out=response.getWriter();

    int  pageNo=Integer.parseInt(request.getParameter("pageNo"));
    int startIndex=pageNo*3-3;

    IEmpDao dao=new EmpDaoImpl();
    List lt=dao.readEmps(startIndex);

    out.println("<center> ");
    out.println("");
    out.println("");
    out.println("");
    Iterator it=lt.iterator();
    while(it.hasNext())
    {
        Employee e=(Employee)it.next();
        out.println("");
        out.println("");
        out.println("");
        out.println("");
        out.println("");

    }
    out.println("<table border="1"><tbody><tr><th>EMPNO</th> <th>ENAME</th> <th>SAL</th> <th>DEPTNO</th></tr><tr><td>"+e.getEmpNo()+"</td><td>"+e.getEName()+"</td><td>"+e.getSalary());
        out.println("</td><td>"+e.getDeptNum()+"</td></tr></tbody></table>");

    long totalRows =dao.getNoOfRows();
    long noOfPages =totalRows/3;
    if(totalRows%3!=0)
    {
        noOfPages++;
    }
    if(pageNo==1)
    {
        int x=pageNo+1;
        out.println("<a href=./PagenationServlet?pageNo="+x+">  Next");
    }
    else if(pageNo==noOfPages)
    {
        int x=pageNo-1;
        out.println("<a href=./PagenationServlet?pageNo="+x+">  Prev");
    }
    else
    {
        int x=pageNo+1;
        out.println("<a href=./PagenationServlet?pageNo="+x+"> Next");
        int y=pageNo+1;
        out.println("<a href=./PagenationServlet?pageNo="+y+"> Next");

    }
}
}

我尝试过：



我正在尝试使用Servlet-HibernateIntegration执行与分页概念相关的程序。但是当我执行程序时，我收到的错误名为 NumberFormatException

推荐答案

试试这个代码< br $>

try this code

int pageNo = 1;
if (request.getParameter("pageNo") != null) {
    pageNo = Integer.parseInt(request.getParameter("pageNo"));
}

而不是

int  pageNo=Integer.parseInt(request.getParameter("pageNo"));

引起错误的原因是，当你的servlet加载时没有页面没有值 varialble

Error is caused due to at first when your servlet load there is no value for pageNo varialble

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