方法重载问题 [英] Method overloading issue

问题描述

写入重载的sumNumber方法，其中一个采用一个3位整数，第二个采用两个3位整数。这些方法应返回各个数字的总和。例如，如果给出的方法值如下：



123



方法应返回6因为1 + 2 + 3 = 6.



我的两个三位数字可以正常工作并加起来很好，但它一直是9，而不是一个不同的值。 />


我尝试过：

Write overloaded sumNumber method, one of which takes a single 3-digit integer, the second which takes two 3-digit integers. These methods should return the sum of the individual numbers. For instance if the method is given a value like:

123

The method should return 6 because 1 + 2 + 3 = 6.

My two three digit numbers work and add up just fine but it keeps coming out as 9 and not a different value.

What I have tried:

package methodoverloading;
/**
 *
 * @author stephenwessels
 */
import java.util.Scanner;
public class MethodOverloading 
{
static int i;
static int j;

public static int GetSum(int a)
{
         i = 234;
         j = 0;
        while (i != 0) 
        {
            j += i % 10;
            i /= 10;
        }
        return i + j;
}

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) 
    {
        Scanner in = new Scanner(System.in);
        System.out.println("Enter two three-digit numbers");
        i = in.nextInt();
        j = in.nextInt();
        System.out.println("The sum of the digits is " + GetSum(i));
    }
    
}

推荐答案

您始终在处理 234 in GetSum 。您应该使用以 a 传递的值。

快速解决方法是更换

You are always processing 234 in GetSum. The value you pass in as a should be used instead.
The quick fix is to replace

i = 234;

with

with

i = a;

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