产品方法重载 [英] Product Method Overloading

问题描述

所以我在CodeHS上解决这个问题，然后我被困了很长时间，所以决定在这里提问.

so I was working on this problem on CodeHS, then I was stuck for so long so decided to ask here.

练习是重载乘积方法，以允许将其他类型的值相乘:

The exercise is to overload the product method to allow for multiplying together other types of values:

1. 两个双打
2. int和double
3. 双精度和整数
4. 三个整数

5. 三双

1. two doubles
2. an int and a double
3. a double and an int
4. three ints

5. three doubles

public class Product extends ConsoleProgram
{
    public void run()
    {
        int intValue = 5;
        double doubleValue = 2.5;

        int product1 = product(intValue, intValue);
        System.out.println(product1);

        // Use method overloading to define methods 
        // for each of the following method calls

        double product2 = product(doubleValue, doubleValue);
        System.out.println(product2);

        int product3 = product(intValue, intValue, intValue);
        System.out.println(product3);

        double product4 = product(intValue, doubleValue);
        System.out.println(product4);

        double product5 = product(doubleValue, intValue);
        System.out.println(product5);

        double product6 = product(doubleValue, doubleValue, doubleValue);
        System.out.println(product6);
    }

    public int product(int one, int two)
    {
        return one * two;
    }
}

谢谢

推荐答案

请注意，重载意味着方法的名称和返回类型与原始方法/初始方法相同.

be aware that overloading means, the name of the method and the return type remains the same as the original/ initial method.

然后您需要定义/实现那些方法>

then you need to define/ implement those methods>

2个双打将是:

public int product(double one, double two)
{
    return (int)(one * two);
}

一个int和一个double将是

an int and a double would be

public int product(int one, double two)
{
    return (int)(one * two);
}

等

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