C ++重载方法指针 [英] C++ overloaded method pointer

问题描述

如何获取方法指针指向某个方法的特定重载：

How do I get a method pointer to a particular overload of a method:

struct A {
    void f();
    void f(int);
    void g();
};

我知道

&A::g

是指向 g 。但是如何获得 f 或 f（int）？

is a pointer to g. But how do I get a pointer to f or f(int)?

推荐答案

(void (A::*)()) &A::f
(void (A::*)(int)) &A::f

函数指针和成员函数指针

function pointers and member function pointers have this feature - the overload can be resolved by to what the result was assigned or cast.

如果函数是静态的，你应该把它们当作普通函数来处理：

If the functions are static, then you should treat them as ordinary functions:

(void (*)()) &A::f;
(void (*)(int)) &A::f;

或甚至

(void (*)()) A::f;
(void (*)(int)) A::f;

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