如果“< ul>”，如何刮除“< ul>”下的内容？没有课 [英] How do you scrape the content under “<ul>” if "<ul>" does not have class

问题描述

我试图获取 ul 下的内容我尝试了下面的代码，当我执行脚本时，它告诉我链接的总量，但它没有然后进一步刮擦。



如果ul有一个类，请说< ul class =list-group> 我只是这样做

Am trying to get the content under "ul" I tried the below code, when I execute the script it tells me the total amount of links but it doesn't scrape further then that.

If the ul had a class let say <ul class="list-group"> I would just simply do this

foreach($html->find('.list-group a') as $element)

所以我的问题是如何让刮刀废弃如果 ul 没有类，则 ul 下的链接。在此先感谢。



这是我试图抓取的内容片段。



Snipt site·GitHub [ ^ ]



我尝试过：

So my question is how do I get the scraper to scrap the links under "ul" if the "ul" doesn't have a class. Thanks in advance.

Here is the content snippet am trying to scrape.

Snipt site · GitHub[^]

What I have tried:

else {
    $html = get_web_page(SITE2_BASE_URL . $path);
    $html = str_get_html($html);
    $result = array();
    foreach($html->find('.series a') as $element)  {
        $result[] = array('title'=> $element->plaintext, 'href'=> $element->href);
    }

推荐答案

html-> find（' .list-group a'） as

html->find('.list-group a') as

element）

所以我的问题是，如果 ul ul 下的链接c $ c>没有课程。在此先感谢。



这是我试图抓取的内容片段。



Snipt site·GitHub [ ^ ]



我尝试过：

So my question is how do I get the scraper to scrap the links under "ul" if the "ul" doesn't have a class. Thanks in advance.

Here is the content snippet am trying to scrape.

Snipt site · GitHub[^]

What I have tried:

else {
    

html = get_web_page（SITE2_BASE_URL。

html = get_web_page(SITE2_BASE_URL .

这篇关于如果“< ul>”，如何刮除“< ul>”下的内容？没有课的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！