如何获取数据到html< ul> <李> < /锂> < / UL>使用php从mysql数据库列出 [英] how to get data to html <ul> <li> </li> </ul> list from mysql database with php
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问题描述
大家好,请在这里需要帮助。我有一个视频播放器,我想从mysql数据库填充视频,这是我的代码。
Hi everybody, pls i need help here. i ve a video player and i want to populate video on it from mysql database, here is my code.
<ul id="playlist1" style="display:none;">
<li data-thumb-source="assets/img/ddd.jpg" data-video-source="assets/video/ddd.mp4" data-poster-source="assets/img/ddd.jpg" data-downloadable="yes">
<div data-video-short-description="">
<div>
<p class="minimalDarkThumbnailTitle">ddd</p>
<p class="minimalDarkThumbnailDesc">dddd.</p>
</div>
</div>
<div data-video-long-description="">
<div>
<p class="minimalDarkVideoTitleDesc">dddd</p>
<p class="minimalDarkVideoMainDesc">ddd</p>
<p>For more information about this please follow <a href="#" target="_blank">this link</a></p>
</div>
</div>
</li>
</ul>
和我这样的mysql数据库
and i ve mysql database like this
id | data-thumb-source | data-video-source | data-poster-source | minimalDarkThumbnailTitle | minimalDarkThumbnailDesc
和php代码从mysql获取数据
and php code to get the data from mysql
<ul>
<?php
$sql = "SELECT * FROM `video`";
foreach ($db->query($sql) as $row) {
$li = '<li> data-thumb-source="' .$row['data-thumb-source']. '"';
$li .= ' class="playlistItem" data-type="local"';
$li .= ' data-video-source="' .$row['data-video-source']. '"';
$li .= ' minimalDarkThumbnailTitle="' .$row['minimalDarkThumbnailTitle']. '"';
$li .= ' minimalDarkThumbnailDesc="' .$row['minimalDarkThumbnailDesc']. '"';
echo $li;
}
$db = null;
?>
</ul>
和视频列表仍为空白,无法显示视频,请帮助我解决问题
and video list is still blank, no video to display, pls help me to get it work
推荐答案
sql = SELECT * FROM`video`;
foreach (
db-> query(
db->query(
sql) as
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