我想将十六进制字符串转换为0x（）形式。 [英] I want to convert hexadecimal string to the form 0x() form.

问题描述

string input = 019F314A

我希望byte []字节等于{0x01,0x9F，0x31,0x4A}

。因为我想制作一个帧格式需要这样的数据。

提前致谢。



我尝试了什么：

string input = 019F314A
I want byte[] bytes to equal { 0x01, 0x9F, 0x31, 0x4A }
.Because i want to make a frame format which required data like that.
Thanks in advance.

What I have tried:

public static byte[] StringToByteArray(String hex)
{
  int NumberChars = hex.Length;
  byte[] bytes = new byte[NumberChars / 2];
  for (int i = 0; i < NumberChars; i += 2)
    bytes[i / 2] = Convert.ToByte(hex.Substring(i, 2), 16);
  return bytes;
}

推荐答案

0x 只是表示代表的符号数字为十六进制

您的函数将返回输出数组为 {1,159,49,74} 这是一个整数数组，并且等效于每个字节符号

0x is just a notation to represent the number as Hex
your function will return the output array as {1,159,49,74} which is an integer array and as well as equivalent to the each byte notation

01 -> 1
9F -> 159
31 -> 49
4A -> 74

假设您希望该值为十六进制表示法，那么您必须将该值转换为字符串为

suppose if you want the value to be in Hex notation then you will have to convert the value to string as

string[] HexString = result.ToList().Select(k => "0x" + k.ToString("x")).ToArray();
        // { "0x1","0x9F", "0x31", "0x4A" }

哪些没用，再一次你必须将它转换成字节才能使用。

参考此在十六进制字符串和数字类型之间转换[ ^ ]

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