将十六进制字符串转换为十六进制int [英] Convert a hex string to a hex int

问题描述

我必须将十六进制字符串转换为十六进制整数，如下所示:

I have to convert a hexadecimal string to a hexadecimal integer, like this:

color = "0xFF00FF" #can be any color else, defined by functions
colorto = 0xFF00FF #copy of color, but from string to integer without changes

我也可以使用RGB格式.

I can have RGB format too.

我有义务这样做，因为该函数在后面执行:

I'm obliged to do this because this function goes after :

def i2s int, len
  i = 1
  out = "".force_encoding('binary')
  max = 127**(len-1)

  while i <= len
    num = int/max
    int -= num*max
    out << (num + 1)
    max /= 127
    i += 1
  end

  out
end

我在此处看到存在十六进制整数.有人可以帮我解决这个问题吗?

I saw here that hexadecimal integers exist. Can someone help me with this problem?

推荐答案

您需要为 String#to_i 方法提供整数基本参数:

You'd need supply integer base argument to String#to_i method:

irb> color = "0xFF00FF"
irb> color.to_i(16)
=> 16711935
irb> color.to_i(16).to_s(16)
=> "ff00ff"
irb> '%#X' % color.to_i(16)
=> "0XFF00FF"

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