将十六进制字符串（char []）转换为int？ [英] Convert hex string (char []) to int?

问题描述

我有一个char []，其中包含一个值，如0x1800785，但我想给该值的函数需要一个int，我如何将它转换为一个int？我已经搜索了，但找不到答案。谢谢。

解决方案

您是否尝试过 strtol（）？ >

strtol - 将字符串转换为长字符整数

示例：

  const char * hexstring =abcdef0; 
 int number =（int）strtol（hexstring，NULL，16）; 
  

如果数字的字符串表示以 0x 前缀，一个必须应该使用0作为基础：

  const char * hexstring = 0xabcdef0; 
 int number =（int）strtol（hexstring，NULL，0）; 
  

（也可以指定一个明确的基础，例如16，但我不建议介绍冗余。）

I have a char[] that contains a value such as "0x1800785" but the function I want to give the value to requires an int, how can I convert this to an int? I have searched around but cannot find an answer. Thanks.

解决方案

Have you tried strtol()?

strtol - convert string to a long integer

Example:

const char *hexstring = "abcdef0";
int number = (int)strtol(hexstring, NULL, 16);

In case the string representation of the number begins with a 0x prefix, one must should use 0 as base:

const char *hexstring = "0xabcdef0";
int number = (int)strtol(hexstring, NULL, 0);

(It's as well possible to specify an explicit base such as 16, but I wouldn't recommend introducing redundancy.)

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