将十六进制字符串 (char []) 转换为 int? [英] Convert hex string (char []) to int?

问题描述

我有一个 char[] 包含一个诸如0x1800785"之类的值，但我想赋予该值的函数需要一个 int，如何将其转换为 int?我已经四处搜索，但找不到答案.谢谢.

I have a char[] that contains a value such as "0x1800785" but the function I want to give the value to requires an int, how can I convert this to an int? I have searched around but cannot find an answer. Thanks.

推荐答案

你试过 strtol() 吗?

strtol - 将字符串转换为长整数

示例:

const char *hexstring = "abcdef0";
int number = (int)strtol(hexstring, NULL, 16);

如果数字的字符串表示以 0x 前缀开头，则 必须 应该使用 0 作为基数:

In case the string representation of the number begins with a 0x prefix, one must should use 0 as base:

const char *hexstring = "0xabcdef0";
int number = (int)strtol(hexstring, NULL, 0);

(也可以指定一个明确的基数，例如 16，但我不建议引入冗余.)

(It's as well possible to specify an explicit base such as 16, but I wouldn't recommend introducing redundancy.)

这篇关于将十六进制字符串 (char []) 转换为 int?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！