无法从视图中访问web api方法? [英] Unable to acces web api method from view?
本文介绍了无法从视图中访问web api方法?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
< html >
< head >
< script type = text / javascript src = 〜/ Scripts / jquery-1.10.2.js > < / script >
< script type = text / javascript >
$( document )。ready(< span class =code-keyword> function (){
$( #btnAdd )。click( function (){
var PersonalDetails = {
id:$( #ID)。val(),
name:$( #Name) .val(),
adres:$( #Adress)。val(),
}
$ .ajax ({
类型: POST,
url: http:// localhost:54516 / api / Values / PostPersonalDetails',
data: JSON .stringify(PersonalDetails),
contentType: application / json; charset = utf-8,
processData: true ,
成功: function (data,status,xhr){
alert( 结果是: + status);
},
错误: function (xhr){
alert(xhr.responseText);
}
});
});
});
< / script >
< / head >
< body >
< h2 > 创建< / h2 >
< div >
< 标签 > Id < / label >
@ Html.TextBox(ID)
< / div >
< div >
< label > 名称< / label >
@ Html.TextBox( 名称)
< / div >
< div >
< label > 年龄< / label >
@ Html.TextBox(地址)
< / div >
< div >
< 按钮 id = btnAdd > 添加< / button >
< / div >
< / body >
< / html >
API控制器代码
public class ValuesController1:ApiController
{
[HttpPost]
public IHttpActionResult PostPersonalDetails([FromBody] PersonalDetails personaldetails)
{
if(!ModelState.IsValid)
{
返回BadRequest(ModelState);
}
SqlConnection co = new SqlConnection(System.Web.Configuration.WebConfigurationManager.ConnectionStrings [con]。ConnectionString);
co.Open();
SqlCommand cmd = new SqlCommand(insert into udata values('+ personaldetails.id +','+ personaldetails.name +','+ personaldetails.adres +'),co);
cmd.ExecuteNonQuery();
co.Close();
返回Ok(personaldetails);
}
}
我尝试了什么: < br $>
i二手网址:
'/ api / Values / PostPersonalDetails'
解决方案
( document )。ready( function (){
( #btnAdd)。click( function (){
var PersonalDetails = {
id:
( < span class =code-string>#ID)。val(),
名跨度>:
<html>
<head>
<script type="text/javascript" src="~/Scripts/jquery-1.10.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#btnAdd").click(function () {
var PersonalDetails = {
"id": $("#ID").val(),
"name": $("#Name").val(),
"adres": $("#Adress").val(),
}
$.ajax({
type: "POST",
url: 'http://localhost:54516/api/Values/PostPersonalDetails',
data: JSON.stringify(PersonalDetails),
contentType: "application/json;charset=utf-8",
processData: true,
success: function (data, status, xhr) {
alert("The result is : " + status);
},
error: function (xhr) {
alert(xhr.responseText);
}
});
});
});
</script>
</head>
<body>
<h2>Create</h2>
<div>
<label>Id</label>
@Html.TextBox("ID")
</div>
<div>
<label>Name</label>
@Html.TextBox("Name")
</div>
<div>
<label>Age</label>
@Html.TextBox("Adress")
</div>
<div>
<button id="btnAdd">Add</button>
</div>
</body>
</html>
API CONTROLLER CODE
public class ValuesController1 : ApiController { [HttpPost] public IHttpActionResult PostPersonalDetails([FromBody]PersonalDetails personaldetails) { if (!ModelState.IsValid) { return BadRequest(ModelState); } SqlConnection co = new SqlConnection(System.Web.Configuration.WebConfigurationManager.ConnectionStrings["con"].ConnectionString); co.Open(); SqlCommand cmd = new SqlCommand("insert into udata values('" +personaldetails.id + "','" +personaldetails.name+ "','" +personaldetails.adres+ "')", co); cmd.ExecuteNonQuery(); co.Close(); return Ok(personaldetails); } }
What I have tried:
i used url:
'/api/Values/PostPersonalDetails'
解决方案
(document).ready(function(){
("#btnAdd").click(function () { var PersonalDetails = { "id":
("#ID").val(), "name":
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