如何在C ++中的最后一个数字/输出循环后删除逗号 [英] How do I remove comma after last number/output loop in C++

问题描述

当我输入

a = 1

b = 20



我的输出总是：

3,9,15 ,.



但我想要的是：

3,9,15



PS：我的英文不好，我希望你们能理解

i只需要一个例子或解决方案



我尝试过：

when i input
a = 1
b = 20

my output is always :
"3 , 9 , 15 , ."

but what i wanted is :
"3 , 9 , 15."

PS : SOrry for my bad english, i hope you guys understand
i just need an example or solution to this program

What I have tried:

int a,b;

cout<< "Number 1 = ";
cin>>a;
cout<< "Number 2 = ";
cin>>b;

if(a<=b)
{
    for(a;a<=b;a++)
    {
        if(a%3==0&&a%2!=0)
        {
            cout<<a;
        }
        if(a<b&&a%3==0&&a%2!=0)
        {
            cout<< " , ";
        }
        else if(a==b)
        {
            cout<< ".";
        }

推荐答案

您可以像这样编写if-else逻辑：

You could write the if-else logic like this :

if( ( a % 3 == 0 ) && ( a % 2 != 0 ) )
{
    cout << a;
    if( a == b )
        cout << ".";
    else
        cout << " , ";
}

首先，稍微分析一下：

'。'将始终打印并始终是最后一个。这意味着简化

First, a little analyze:
The '.' will be always printed and always be last. Which means simplification

if(a<=b)
{
    for(a;a<=b;a++)
    {
        if(a%3==0&&a%2!=0)
        {
            cout<<a;
            if(a<b)
            {
                cout<< " , ";
            }
        }
    }
    cout<< ".";
}

代码中的问题是无需打印 b 。

这个有很多解决方案

- 如果你在一个数字后打印逗号，你需要确保下一个数字要打印。

- 如果玩具在数字前打印逗号，你需要确保它不是第一个。

The problem in your code is that b will not necessary be printed.
There is many solution around this
- if you print the comma after a number, you need to make sure there will be a next number to print.
- if toy print the comma before a number, you need to make sure it is not the first.

谢谢你们，但我已经得到了我的解决方案

Thanks guys but i already got my solution to put

char const*sep = ""

....
for(a;a<=b;a++)
    	{
		if(a%3 == 0 && a%2 != 0)
    		{		   
       		        cout << sep << a; 
       			sep = ", ";
    		}
    	}

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